Construct the data tables for the first and second  derivative plots from 21.1 mL to 22.0 mL only.  b. Graph the first and second derivative plots from 21.1  mL to 22.0 mL.  c. Determine the equivalence point from the first and  second derivative data.

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter15: Additional Aqueous Equilibria
Section: Chapter Questions
Problem 93QRT: When 40.00 mL of a weak monoprotic acid solution is titrated with 0.100-M NaOH, the equivalence...
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a. Construct the data tables for the first and second 
derivative plots from 21.1 mL to 22.0 mL only. 
b. Graph the first and second derivative plots from 21.1 
mL to 22.0 mL. 
c. Determine the equivalence point from the first and 
second derivative data.

A 0.2005-g crude sample of a monoprotic acid, kobeicin, was dissolved in 200.0 mL of
water. Then, the resulting solution was titrated using 0.0490 M NaOH via potentiometric
titration. A portion of the data is shown below.
4. Titration data of kobeicin
V, mL pH
V, mL pH
10.1
3.16
21.1
5.09
10.2
3.17
21.2
5.28
10.3
3.18
21.3
5.64
10.4
3.19
21.4
8.91
10.5
3.19
21.5
9.68
10.6
3.20
21.6
9.95
10.7
3.21
21.7
10.11
10.8
3.22
21.8
10.23
10.9
3.23
21.9
10.32
11.0
3.24
22.0
10.40
Transcribed Image Text:A 0.2005-g crude sample of a monoprotic acid, kobeicin, was dissolved in 200.0 mL of water. Then, the resulting solution was titrated using 0.0490 M NaOH via potentiometric titration. A portion of the data is shown below. 4. Titration data of kobeicin V, mL pH V, mL pH 10.1 3.16 21.1 5.09 10.2 3.17 21.2 5.28 10.3 3.18 21.3 5.64 10.4 3.19 21.4 8.91 10.5 3.19 21.5 9.68 10.6 3.20 21.6 9.95 10.7 3.21 21.7 10.11 10.8 3.22 21.8 10.23 10.9 3.23 21.9 10.32 11.0 3.24 22.0 10.40
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