Chapter7: Statistical Data Treatment And Evaluation
Section: Chapter Questions
Problem 7.10QAP
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Question
![Part A: Determination of a Calibration Curve
Stnd:
[Fe(SCN)2+]
Absorbance
1
0.000000
0.000
0.000090
0.432
3.
4.
0.000106
0.480
0.000127
0.633
5n
0.000189
0.831
6.
0.000204
0.8
Calibration Curve
1.000
0.900
y= 4339.8x + 0.0258
R 0.9904
0.800
0.700
0.600
0.500
0.400
0.300
0.200
0.100
Absorbance](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feb39a791-932a-40e9-8866-3329ef2f764e%2Fbdc81fdd-8576-439b-98b2-967b69ec9c40%2F44ojrk7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Part A: Determination of a Calibration Curve
Stnd:
[Fe(SCN)2+]
Absorbance
1
0.000000
0.000
0.000090
0.432
3.
4.
0.000106
0.480
0.000127
0.633
5n
0.000189
0.831
6.
0.000204
0.8
Calibration Curve
1.000
0.900
y= 4339.8x + 0.0258
R 0.9904
0.800
0.700
0.600
0.500
0.400
0.300
0.200
0.100
Absorbance
![(ISCN
Data Report Sheet: Spectrophotometric Determination of an Equilibrium
Constant.
Part A: Determination of a Calibration Curve;
Stnd.1
Std. 2
Stnd. 3
Stnd 4
Sind. 5
Stad. 6
(Но)
0.000090
0.000106 0.000127 0.000189 0.000204
(Fe(SCN)"]
Column A
0.432
0.480
0.633
0.831
0.887
Absorbance
Column E
0.
y= 4339.8x + 0.0258
Equafion of Calibration Line:
0.9904
Correlation Coefficient;
4339.8
Slope (br):
Part B: Determination of K
Expt. 1
Еxpt, 2
Expt. 3
Expt. 4
Expt. 5
0,00165
0.00165
0.00165
0.00165
000165
(Table 1)
0.00033
0.00066
0.00099
0.001
0.00165
ISCN at
(Table 1)
0.290
0.524
0.803
1.024
1.199
[Fe(SCN)*l
Column F
|Fe"leqt
148.6799
135.1678
142.2659
141 8466
134.2843
Average K:140 448
I](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feb39a791-932a-40e9-8866-3329ef2f764e%2Fbdc81fdd-8576-439b-98b2-967b69ec9c40%2Fu2tko4g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(ISCN
Data Report Sheet: Spectrophotometric Determination of an Equilibrium
Constant.
Part A: Determination of a Calibration Curve;
Stnd.1
Std. 2
Stnd. 3
Stnd 4
Sind. 5
Stad. 6
(Но)
0.000090
0.000106 0.000127 0.000189 0.000204
(Fe(SCN)"]
Column A
0.432
0.480
0.633
0.831
0.887
Absorbance
Column E
0.
y= 4339.8x + 0.0258
Equafion of Calibration Line:
0.9904
Correlation Coefficient;
4339.8
Slope (br):
Part B: Determination of K
Expt. 1
Еxpt, 2
Expt. 3
Expt. 4
Expt. 5
0,00165
0.00165
0.00165
0.00165
000165
(Table 1)
0.00033
0.00066
0.00099
0.001
0.00165
ISCN at
(Table 1)
0.290
0.524
0.803
1.024
1.199
[Fe(SCN)*l
Column F
|Fe"leqt
148.6799
135.1678
142.2659
141 8466
134.2843
Average K:140 448
I
Expert Solution
Step 1
Equation obtained from the calibration curve is y = 4339.8x + 0.0258 where
y = Absorbnace
x = [FeSCN2+]
Experiment 1
y = 0.290
0.290 = 4339.8x + 0.0258
x = 0.000061
So,
[FeSCN2+]eq = x = 0.000061 M
Now,
Fe3+ + SCN- FeSCN2+
| [Fe3+] | [SCN-] | [FeSCN2+] | |
| Initial | 0.00165 | 0.00033 | 0 |
| Change | -x | -x | +x |
| Equillibrium | 0.00165-x | 0.00033-x | x |
So,
[Fe3+]eq = (0.00165-0.000061) = 0.00159 M
[SCN-]eq = 0.000269 M
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