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Continue with the last question about the interconversion between A and B, suppose the rate constants are ką= 13000s-1 and kb= 3018s-1, calculate the equilibrium constant K. Please enter your answer with 1 decimals

Continue with the last question about the interconversion between A and B, suppose the rate constants are ką= 13000s-1 and kb= 3018s-1, calculate the equilibrium constant K. Please enter your answer with 1 decimals

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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QUESTION 6 Continue with the last question about the interconversion between A and B, suppose the rate constants are k₂= 13000s-1 and kb=3018s-1, calculate the equilibrium constant K. Please enter your answer with 1 decimals 0.98
Transcribed Image Text:QUESTION 6 Continue with the last question about the interconversion between A and B, suppose the rate constants are k₂= 13000s-1 and kb=3018s-1, calculate the equilibrium constant K. Please enter your answer with 1 decimals 0.98
Expert Solution
Step 1

Given, that interconversion occurs between A and B so the reaction is-

A⇆kbkaB

Here, the respective rate constants for forward and bacwkard reactions are-

ka=13000 s-1

kb=3018 s-1 

Hence, equilibrium constant for the reaction is calculated as-

keq=kakb 

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