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- #4. answer is on bracket. thank uPlease answer super fast and answer all questions and show calculations For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.4664- Please I want answer sub-parts (c) and (d) with steps and clear typing or hand writing. Many thanks
- Can someone answer nos. 5 to 10? Thank you very much! If it's not too much, provide an explanation for each number. Thanks!Answer #1 and #2. Prioritize answering #2.Second-degree Equation Step 1. Copy the given table on your graphing paper, after your student details. X (% concentration) 0.50 1.00 1.50 2.00 2.50 3.00 Y (oil separation) 5.10 3.60 2.60 2.00 1.40 1.00 Log Y Step 2. Initially plot the x and y values on a regular graphing paper (or millimeter graphing paper - if available, preferred for precision). Label then connect the points to observe curved line. Step 3. Since the line is curved, the y-intercept cannot be easily determined because you can’t exactly determine the direction of the line once extrapolated. To obtain a straight line, first, compute the logarithm values of all the y values up to the 2nd decimal place (for the purpose of easy plotting later) and fill in the table. Step 4. On another graphing paper, plot then label the x and log y. Using a dotted line, extrapolate the straight line to the y axis. Label this point as “a” for the y-intercept. Step 5.…