Solve the attached problem CountrySri LankaChinaVietnamGreat BritainNorwayRomaniaSwitzerlandArmeniaNetherlandsIndiaGeorgiaKyrgyzstanCosta RicaBrazilUzbekistanGoldmedals051019342070301CountryThailandKuwaitBahamasKenyaTrinidad and TobagoGreeceMozambiqueKazakhstanDenmarkLatviaCzech RepublicHungarySwedenUruguayUnited StatesGoldmedals20050022133036(a) Make a dotplot to display these data. Describe theoverall pattern of the distribution and any deviationsfrom that pattern.(b) Overall, 204 countries participated in the 2008Summer Olympics, of which 55 won at least one goldmedal. Do you believe that the sample of countrieslisted in the table is representative of this larger popu-lation? Why or why not?

Given the data as Country Gold medals Sri Lanka 0 China 51 Vietnam 0 Great Britain 19…

Answered: Country Sri Lanka China Vietnam Great…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Find the first and second derrivative
A politician asked his constituents via a Facebook poll to help him how he should vote on a bill that would establish 150m Protester Exclusion Zones around abortion clinics in New South Wales, Australia. On his Facebook page, Philip Donato stated “I believe this is a matter of conscience and the views of my electorate should supersede my own.” After the poll closed, the final Facebook poll results had 78%78% of the 1960019600 voters indicating support for the Protester Exclusion Zones. Use our quick and approximate method to determine the margin of error for the final Facebook poll results. Give your answer as a percentage precise to two decimal places.
There is few typo in question , ignore them
#9;review ch7
Regular Coke Diet Coke Regular Pepsi Diet Pepsi 0.8192 0.7773 0.8258 0.7925 0.8150 0.7758 0.8156 0.7868 0.8163 0.7896 0.8211 0.7846 0.8211 0.7868 0.8170 0.7938 0.8181 0.7844 0.8216 0.7861 0.8247 0.7861 0.8302 0.7844 0.8062 0.7806 0.8192 0.7795 0.8128 0.7830 0.8192 0.7883 0.8172 0.7852 0.8271 0.7879 0.8110 0.7879 0.8251 0.7850 0.8251 0.7881 0.8227 0.7899 0.8264 0.7826 0.8256 0.7877 0.7901 0.7923 0.8139 0.7852 0.8244 0.7852 0.8260 0.7756 0.8073 0.7872 0.8227 0.7837 0.8079 0.7813 0.8388 0.7879 0.8044 0.7885 0.8260 0.7839 0.8170 0.7760 0.8317 0.7817 0.8161 0.7822 0.8247 0.7822 0.8194 0.7874 0.8200 0.7742 0.8189 0.7822 0.8172 0.7833 0.8194 0.7839 0.8227 0.7835 0.8176 0.7802 0.8244 0.7855 0.8284 0.7892 0.8244 0.7859 0.8165 0.7874 0.8319 0.7775 0.8143 0.7907 0.8247 0.7833 0.8229 0.7771 0.8214 0.7835 0.8150 0.7870 0.8291 0.7826 0.8152 0.7833 0.8227 0.7815 0.8244 0.7822 0.8211 0.7791 0.8207 0.7837…
According to the Department of Motor Vehicles (DMV), the entity in charge ofprovidingdrivinglicensesintheUnitedStates,itisillegaltodrivewithabloodalcoholcontentof0.08%ormoreif you are 21 or older. In the DMV’s guidelines to determine when a person is driving under the inﬂuence, itisindicatedthatfewer than ﬁve percent of the population weighing 100 pounds will exceed the 0.33 alcohol level. Assume this is accurate. If the Highway Patrol stops in a random day 200 unrelated cars where the individual weighs one hundred pounds, on a Friday night, what is the probability that six percent of more individuals stopped exceeds that 0.33 alcohol level?
Petal length (in cm) of Iris virginica: x1; n1 = 36 5.0 5.6 6.1 6.1 5.1 5.5 5.3 5.5 6.9 5.0 4.9 6.0 4.8 6.1 5.6 5.1 5.6 4.8 5.4 5.1 5.1 5.9 5.2 5.7 5.4 4.5 6.4 5.3 5.5 6.7 5.7 4.9 4.8 5.7 5.3 5.3 Petal length (in cm) of Iris setosa: x2; n2 = 38 1.6 1.6 1.4 1.5 1.5 1.6 1.4 1.1 1.2 1.4 1.7 1.0 1.7 1.9 1.6 1.4 1.5 1.4 1.2 1.3 1.5 1.3 1.6 1.9 1.4 1.6 1.5 1.4 1.6 1.2 1.9 1.5 1.6 1.4 1.3 1.7 1.5 1.7 Let ?1 be the population mean for x1 and let ?2 be the population mean for x2. Find a 99% confidence interval for ?1 − ?2. (Round your answers to two decimal places.) lower limit: upper limit: Which distribution did you use? Why? A) The standard normal distribution was used because ?1 and ?2 are unknown. B) The Student's t-distribution was used because ?1 and ?2 are known. C) The Student's t-distribution was used because ?1 and ?2 are unknown. D) The standard normal distribution was used because ?1 and ?2 are known. Do you need information about the petal length…
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#7 review ch7
Date DJIA S&P 500 Day 1 35405.24 4536.54 Day 2 35629.33 4579.38 Day 3 35111.16 4467.44 Day 4 35089.74 4510.53 Day 5 35091.13 4493.87 Day 6 35462.78 4511.54 Day 7 35768.06 4577.18 Day 8 35241.59 4514.08 Day 9 34738.06 4408.64 Day 10 34566.17 4411.67 Day 11 34988.84 4461.07 Day 12 34934.27 4485.01 Day 13 34312.03 4390.26 Day 14 34079.18 4358.87 Day 15 33596.61 4314.76 Day 16 33131.76 4235.50 Day 17 33223.83 4278.70 Day 18 34058.75 4394.65 Day 19 33892.60 4363.94 Day 20 33294.95 4316.26 Day 21 33891.35 4396.54 Day 22 33794.66 4353.49 Day 23 33614.80 4318.87 Day 24 32817.38 4211.09 Day 25 32632.64 4180.70 Day 26 33286.25 4287.88 Day 27 33174.07 4249.52 Day 28 32944.19 4194.31 Day 29 32945.24 4183.11 Day 30 33544.34 4252.45 Day 31 34063.10 4367.86 Day 32 34480.76 4421.67 Day 33 34754.93 4473.12 Day 34 34552.99 4471.18 Day 35 34807.46 4521.61 Day 36 34358.50 4466.24 Day 37 34707.94 4510.16 Day 38 34861.24 4553.06…
58 Household Paper Plastic 1 11.08 12.47 2 9.41 3.36 3 13.61 8.95 4 8.82 11.89 5 2.8 5.92 6 7.57 5.92 7 7.98 6.09 8 13.31 19.7 9 11.42 12.81 10 12.73 14.83 11 16.39 9.7 12 6.33 3.86 13 8.72 9.2 14 14.33 6.43 15 3.27 0.63 16 9.55 9.2 17 12.43 8.57 18 20.12 18.35 19 6.16 5.88 20 6.38 8.82 21 6.98 2.65 22 12.32 11.17 23 17.65 11.26 24 15.09 9.11 25 9.19 3.74 26 13.05 12.31 27 9.83 6.26 28 6.44 8.4 29 11.36 10.25 30 16.08 14.36 Identify the test statistic: Identify the P Value: Since the P-value is (greater,less than) the significance level, (fail to reject, reject) the null hypothesis. There (is not, is) sufficient evidence to support the claim that there is a difference between the weights of discarded paper and discarded plastic.
A manuscript that has been rejected by a journal: a. can be revised and resubmitted b. cannot be resubmitted to the same journal without an invitation from the editor c. can be requested to be re-reviewed by a different set of peers within the same journal d. can be reconsidered if an additional fee is paid

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