13. Critical values of the Chi-square distributionwith d degrees of freedomProbability of exceeding the critical valued0.05 0.010.001d13.841 6.635 10.82825.991 9.210 13.81637.815 11.345 16.26649.488 13.277 18.467511.070 15.086 20.515612.592 16.812 22.45814.067 18.475 24.32278915.507 20.090 26.12516.919 21.666 27.87710 18.307 23.209 29.588INTRODUCTION TO POPULATION GENETICS, Table D.10.05 0.010.0011119.675 24.725 31.26412 21.026 26.217 32.91013. 22.362 27.688 34.5281423.685 29.141 36.1231524.996 30.578 37.6971626.296 32.000 39.252181917 27.587 33.409 40.79028.869 34.805 42.31230.144 36.191 43.82020 31.410 37.566 45.315A chi-squared test was done. The degrees of freedom was 3 and the chi-squared teststatistic calculated was 7.5. Based on critical values and a traditional (0.05) alphalevel of significance, what is the interpretation of these results?reject the null hypothesisfail to reject the null hypothesisnot enough information is given

Degree of freedom =df =3 Test statistic χ2 =7.5

Answered: Critical values of the Chi-square…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Decreasing the alpha level (for example from = .05 to = .01) ____. a Decreases the probability of a Type I error b Decreases the size of the critical region c Decreases the probability that the sample will fall into the critical region d All of the other options are results of decreasing alpha.
Test a claim that the mean amount of carbon monoxide in the air in U.S cities is less than 2.33 parts per million. It was found that the mean amount of carbon monoxide in the air for the random sample of 63 cities is 2.38 parts per millionband the standard deviation is 2.12 parts per million. At a= 0.01, can the claim be supported? Assume population is normally distributed. i) Identify the claim and state Ho and Ha ii) Find the critical value(s) and identify the rejection region(s). iii) Find the standardized test statistic, t. iv) Decide wheter to reject or fail to reject the null hypothesis. v) Interpret the decision in the context if the original claim.
Lifetime of electronics: In a simple random sample of 100 electronic components produced by a certain method, the mean lifetime was 125 hours. Assume that component lifetimes are normally distributed with population standard deviation σ=20 hours. Round the critical value to no less than three decimal places.
(a) state the null and the alternative hypothesis(b) compute the test statistic, (c) determine the critical value and sketch therejection region and the non-rejection region using the normal curve. Show the 3-step procedures. A rural health unit surveyed the heights of the male aged 18 to 24 years old. It was found out that the mean height of males aged 18 to 24 years old was 70 inches. If a random sample of 20 males aged 18 to 24 years old had a mean height of 65 inches with a standard deviation of 3. Use 1% level of significance.
Test a claim that the mean amount of carbon monoxide in the air in U.S. cities is less than 2.32 parts per million. It was found that the mean amount of carbon monoxide in the air for the random sample of 64 cities is 2.38 parts per million and the standard deviation is 2.12 parts per million. At α=0.01, can the claim be supported? Complete parts (a) through (e) below. Assume the population is normally distributed. a. Identify Ho and Ha b. find the critical values and sket the rejection region c. calculate the test statistic d. Do you "reject the Ho" or "fail to reject Ha"? e. interpret results ( does it support or reject the claim)
1.)At α=0.05, Use the distribution table to find the critical values for the rejection regiontc=____ (use 4 decimal places) 2.) What is your conclusion? Accept the alternative hypothesis and reject the claim Accept the null hypothesis and support the claim Fail to reject the null hypothesis and do not support the claim Reject the null hypothesis and support the claim Reject the alternative hypothesis and support the claim
1.) At α=0.05 , Use the distribution table to find the critical values for the rejection regiontc=______ (use 4 decimal places) 2.) What is your conclusion? Accept the alternative hypothesis and reject the claim Reject the alternative hypothesis and support the claim Reject the null hypothesis and support the claim Fail to reject the null hypothesis and do not support the claim Accept the null hypothesis and support the claim
Find the indicated z score. The graph depicts the standard normal distribution with mean 0 and standard deviation 1. z 0.2090 0 A symmetric bell-shaped curve is plotted over a horizontal scale with two labeled coordinates. One coordinate is labeled "0" and is located at the center and peak of the curve. The other coordinate is labeled "z," and is to the right of 0. A vertical line extends from the scale to the curve at z. The area under the curve to the right of z is shaded and labeled “0.2090.” Question content area bottom Part 1 The indicated z score is enter your response here. (Round to two decimal places as needed.)
4. Find the indicated z score. The graph depicts the standard normal distribution with mean 0 and standard deviation 1. z 0.2514 0 A symmetric bell-shaped curve is plotted over a horizontal scale with two labeled coordinates. One coordinate is labeled "0" and is located at the center and peak of the curve. The other coordinate is labeled "z," and is to the left of 0. A vertical line extends from the scale to the curve at z. The area under the curve to the left of z is shaded and labeled “0.2514.” The indicated z score is nothing. (Round to two decimal places as needed.)
Cigarette Smoking A researcher found that a cigarette smoker smokes on average 31 cigarettes a day. She feels that this average is too high. She selected a random sample of 8 smokers and found that the mean number of cigarettes they smoked per day was 28. The sample standarddeviation was 2.9. At =α0.01, is there enough evidence to support her claim? Assume that the population is approximately normally distributed. Use the critical value method and tables. (a)State the hypotheses and identify the claim. (b)Find the critical value. (c)Compute the test value (d)Make the decision. (e)Summarize the results.
Data set 27 “M&M” weights in Appendix B lists data from 100 M&Ms and 27% of them are blue. The Mars candy company states that the percentage of blue M&Ms is equal to 24%. Test this claim using a significance level of α = 0.05. 4. Sketch a normal distribution curve, plot the critical value and highlight the critical or rejection region. Calculate the test stastic z - what is it? On your graph, plot the z test stastic. Does it lie inside or outside the critical region? 5. State a conclusion about the null hypothesis - reject or fail to reject H0? 6. Should the Mars company take corrective action? Why or why not? 7. What is the p-value associated with this test statistic z? 8. Based on this p-value, would you reject H0 or fail to reject H0? Why or why not?
Diameters data frame of the first sample (showing only the first five observations) diameters 0 3.30 1 2.82 2 1.98 3 1.41 4 2.75 Diameters data frame of the second sample (showing only the first five observations) diameters 0 2.91 1 2.14 2 3.39 3 1.82 4 2.35 test-statistic = -0.44 two tailed p-value = 0.6625 Suppose that the factory claims that the proportion of ball bearings with diameter values less than 2.20 cm in the existing manufacturing process is the same as the proportion in the new process. At alpha=0.05, is there enough evidence that the two proportions are the same? Perform a hypothesis test for the difference between two population proportions to test this claim. In your initial post, address the following items: Define the null and alternative hypotheses in mathematical terms as well as in words. Identify the level of significance. Include the test statistic and the P-value. See Step 2 in the Python script. (Note that Python methods return two tailed P-values. You must…

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