Current Attempt in Progress Examine the following reaction. 3 CO 2(8) + 2 Fe(s) = Fe 203(s) +3 CO(8) What is the equilibrium expression for the reaction? O K = (Fe,O3][CO} /([Fe] [CO,1) O K = (CO2)/[COJ OK = [CO2/[Coj3 O K - (Fe]/[Fe2O3] O K- (CO]/[CO21 O K = [Fe,O3][CO]/ ([Fe] [CO2]) O K= (Fe2O3]/[Fe] O K = (Fe] [CO2)/([Fe2O3][CO]) O K = [CO)/[CO2] O K = [Fej? [CO2J3/ ([Fe,Og)[CO]) %3D

Chemistry: Principles and Reactions
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Chapter12: Gaseous Chemical Equilibrium
Section: Chapter Questions
Problem 13QAP: Consider the following reaction at 250C: A(s)+2B(g)C(s)+2D(g) (a) Write an equilibrium constant...
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Current Attempt in Progress
Examine the following reaction.
3 CO 2(8)+2 Fe(s) Fe 203(s) +3 CO(g)
What is the equilibrium expression for the reaction?
O K = [Fe,O3][CO18 / ([Fe]? [CO,1)
O K = [CO2)/[CO]
OK = [CO2]8 /[cOJ
O K = (Fe]/[Fe2O3]
O K = [CO]/[CO2)
O K= [Fe,O3][CO]/ ([Fe] [CO,)
O K = [Fe2O3]/[Fe]
O K = [Fe] [CO2)/ ([Fe,O3] [CO])
O K = [CO] /[CO2]
O K = (Fe] [CO21³/ ((Fe,O3] [CO]³)
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Transcribed Image Text:View Policies Current Attempt in Progress Examine the following reaction. 3 CO 2(8)+2 Fe(s) Fe 203(s) +3 CO(g) What is the equilibrium expression for the reaction? O K = [Fe,O3][CO18 / ([Fe]? [CO,1) O K = [CO2)/[CO] OK = [CO2]8 /[cOJ O K = (Fe]/[Fe2O3] O K = [CO]/[CO2) O K= [Fe,O3][CO]/ ([Fe] [CO,) O K = [Fe2O3]/[Fe] O K = [Fe] [CO2)/ ([Fe,O3] [CO]) O K = [CO] /[CO2] O K = (Fe] [CO21³/ ((Fe,O3] [CO]³) %3D %3D !! Save for Later
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