Cwi = 120 pF Cwo 10 pF Cbe = 40 pF Cbc = 10pF = 14pF Cce == 1. 5 ΚΩ 15 V www 4.7kΩ B = 100 1 μF - 4 V Vi 5.6n F 330 Ω Figure Q2(a) HH Vs www Vo 1 ΚΩ

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ISBN:9780133923605
Author:Robert L. Boylestad
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Cwi = 120 pF
Cwo = 10 pF
Cbe=40 pF
Cbc = 10pF
Cce = 14pF
1. 5 ΚΩ
15 V
4.7kQ2
B = 100
1 µF
- 4 V
Vi
5.6 n F
330 Ω
Figure Q2(a)
+
Vs
Vo
1 ΚΩ
Transcribed Image Text:Cwi = 120 pF Cwo = 10 pF Cbe=40 pF Cbc = 10pF Cce = 14pF 1. 5 ΚΩ 15 V 4.7kQ2 B = 100 1 µF - 4 V Vi 5.6 n F 330 Ω Figure Q2(a) + Vs Vo 1 ΚΩ
(a)
By referring to Figure Q2(a), analyze;
(i)
(ii)
a.c. resistance diode, re
a.c. equivalent circuit.
(iii) midband gain, Avmid.
(v)
(iv) low frequency response, fLE, and fic.
high frequency response, fHi and fHo.
Given Ci Cwi + Cce + Cbe and Co= Cwo + Cce + Cbc
1
2πRC
Basic Frequency Filter Equation: f
=
Transcribed Image Text:(a) By referring to Figure Q2(a), analyze; (i) (ii) a.c. resistance diode, re a.c. equivalent circuit. (iii) midband gain, Avmid. (v) (iv) low frequency response, fLE, and fic. high frequency response, fHi and fHo. Given Ci Cwi + Cce + Cbe and Co= Cwo + Cce + Cbc 1 2πRC Basic Frequency Filter Equation: f =
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