Using 64×8 ROM chips with an enable input, construct a 512×8 ROM with eight chips and a decoder.
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Using 64×8 ROM chips with an enable input, construct a 512×8 ROM with eight chips and a decoder.
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- You buy a ROM memory chip that is 64Kx8. How many memory address lines does the chip have? A 16 B 64K C 512 D 8Memory Capacity: 64 bytes of RAM and 64 bytes of ROM Chips Available: 32x8 RAM and 64x8 ROM Show how the address lines and how the RAM and ROM chips will be selected.Microprocessor , For a data segments for an 8086 µP memory system has 64 kB size, with segment address is 1234 H. Find the offset for a memory address 125FC H.
- 1. Design 8086’s memory system consisting of 64K bytes of ROM using32KX8 chip. The memory is to reside over the address range 60000Hthrough 6FFFFH. Select suitable address maps.2. If the memory chip size is 1024 X 4 bits, how many chips are required tomakeup 2K bytes of memory?3. Interface 16 K word of memory to the 8086-microprocessor system.Available memory chips are 8 K X 8 RAM. Draw the memory table.Design a 512 k byte memory using 64 k byte chips. Show the internal design of the 64kbyte chips.How many address lines at required for a 16M x 8 ROM chip? A.16M B.23 C.21 D.24 E.13 F.11 G.14 H.8
- A memory chip from a digital camera has 25 bistable (ON-OFF) memory elements. What is the total number of ON-OFF configurations?5. Make a circuit of the inverter, AND gate, and OR gate to produce the following output:a. (x + y)'xb. xyz + x'y'z'Using logic gates, design an active low chip select for the memory a 256 K memory device starting at address 38000016 in a 16 Megabyte memory space.
- Calculate the address of the bit 58 H in the bit addressable area of the 8051? Show your calculation.Eight memory chips of 32*4 bit size have their address buses connected together. What is the size of the memory system ?What is the starting and ending address of a 256K x 8 memory? How many address lines will be required to interface this memory with 8086? Also, draw the interfacing diagram with 8086