(d) Calculate the error sum of squares, which is a measure of within SSE = (use four decimals in your answer) (e) Complete the ANOVA table. Note that you've already found two of the three sums of squares. Use four the F test statistic to 2 decimals. The appropriate hypotheses are: O Ho: 12 = μ3 = μ¹4 Ha: 1

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STATISTICS(UPVOTE WILL BE GIVEN. PLEASE ANSWER THE FOLLOWING PROBLEMS. FOLLW THE INSTRUCTION CAREFULLY NO LONG EXPLANATION NEEDED. BOX THE FINAL ANSWERS.)
(d) Calculate the error sum of squares, which is a measure of within
SSE =
(use four decimals in your answer)
(e) Complete the ANOVA table. Note that you've already found two of the three sums of squares. Use four
the F test statistic to 2 decimals.
The appropriate hypotheses are:
O Ho: 12 = 13 = μ¹4
Ha: H1
H₂ H3 <H4
O Ho: 1 =
H₂: 141
Source of Variation
Treatment
Error
Total
₂ = μ3 = μ¹4
14₂ 143 144
(f) Do the data provide convincing evidence that the mean rating associated with the game description by
rating labels? Test the appropriate hypotheses using a significance level of 0.025.
sample variation.
df
O Ho: 1 = 2 = μ3 = μ¹4
Ha: all of the population means are different
O Ho: H1 H2 = 3 = 4
Sum of Squares
Transcribed Image Text:(d) Calculate the error sum of squares, which is a measure of within SSE = (use four decimals in your answer) (e) Complete the ANOVA table. Note that you've already found two of the three sums of squares. Use four the F test statistic to 2 decimals. The appropriate hypotheses are: O Ho: 12 = 13 = μ¹4 Ha: H1 H₂ H3 <H4 O Ho: 1 = H₂: 141 Source of Variation Treatment Error Total ₂ = μ3 = μ¹4 14₂ 143 144 (f) Do the data provide convincing evidence that the mean rating associated with the game description by rating labels? Test the appropriate hypotheses using a significance level of 0.025. sample variation. df O Ho: 1 = 2 = μ3 = μ¹4 Ha: all of the population means are different O Ho: H1 H2 = 3 = 4 Sum of Squares
:) Use the accompanying Minitab output to obtain the equation of the least squares line for predicting strength from modulus of elasticity. (Enter your slope to five
decimal places, and your intercept to four decimal places.)
Predictor
Constant
Coef
3.2925
mod elas
0.10748
s = 0.8657 R-sq 73.8%
Analysis of Variance
SOURCE
DF
Regression
1
25
26
Error
Total
Stdev
0.6008
0.01280
y = 0.1075x + 3.2908
SS
52.870
18.736
71.605
t-ratio
P
5.48
0.000
8.40
0.000
R-sq (adj) = 72.8%
MS
52.870
0.749
F
70.55
P
0.000
Predict strength for a beam whose modulus of elasticity is 65. (Round your answer to two decimal places.)
Would you feel comfortable using the least squares line to predict strength when modulus of elasticity is 100? Explain.
No, this value is way beyond of the range the y values of the data values.
O No, this value is way beyond of the range the x values of the data values.
O Yes, this value is inside of the range the x values of the data values.
O Yes, this value is inside of the range the y values of the data values.
X
Transcribed Image Text::) Use the accompanying Minitab output to obtain the equation of the least squares line for predicting strength from modulus of elasticity. (Enter your slope to five decimal places, and your intercept to four decimal places.) Predictor Constant Coef 3.2925 mod elas 0.10748 s = 0.8657 R-sq 73.8% Analysis of Variance SOURCE DF Regression 1 25 26 Error Total Stdev 0.6008 0.01280 y = 0.1075x + 3.2908 SS 52.870 18.736 71.605 t-ratio P 5.48 0.000 8.40 0.000 R-sq (adj) = 72.8% MS 52.870 0.749 F 70.55 P 0.000 Predict strength for a beam whose modulus of elasticity is 65. (Round your answer to two decimal places.) Would you feel comfortable using the least squares line to predict strength when modulus of elasticity is 100? Explain. No, this value is way beyond of the range the y values of the data values. O No, this value is way beyond of the range the x values of the data values. O Yes, this value is inside of the range the x values of the data values. O Yes, this value is inside of the range the y values of the data values. X
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