A pendulum with a cord of length r = 1.05 m swings in a vertical plane (see figure). When the pendulum is in the two horizontal positions 0 = 90° and 0 = 270°, its speed is 4.95 m/s.a(a) Find the magnitude of the radial acceleration (in m/s2) for these positions.m/s2(b) Find the magnitude of the tangential acceleration (in m/s?) for these positions.m/s?(c)Draw a vector diagram to determine the direction of the total acceleration for these two positions. atata-aratarààa,0 = 90°0 = 270°e = 90 °0 = 270°0 = 90°e = 270a,8 = 90°e = 270°(d) Calculate the magnitude (in m/s2) and direction (in degrees above or below the horizontal) of the total acceleration.magnitudem/s?directionO --Select--- •the horizontal

Answered: Image /qna-images/answer/ffeabfc0-d9cc-4898-9a47-5f33b44f8e60.jpg

Answered: (d) Calculate the magnitude (in m/s?)…

Engineering

Mechanical Engineering

(d) Calculate the magnitude (in m/s?) and direction (in degrees above or below the hor

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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