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Please explain part D
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- Dapsone tablets, labelled 50 mg has an average tablet weight of 0.6509 g. 2.0g of powdered tablets reacted (see reaction below) with 26.05 mL of 0.0506N sodium nitrite (NaNO2) solution. Determine the amount of Dapsone as a percentage of the Label Strength (or Label Claim). Report your answer to 1 decimal place. Given: Dapsone molar mass, 248.302 g/mol Dapsone structure Reaction: Sodium nitrite (NaNO2) reacts with hydrochloric acid (HCl) to generate nitrous acid (HNO2). NaNO2 + HCl ® HNO2 + NaCl Nitrous acid (HNO2) then reacts with each amino group on Dapsone, and an indicator indicates the endpoint. R-NH2 (full structure shown above) + HNO2 + HCl ® R-N2Cl + 2H2ONa2CO3(aq) +2HCl(aq) 2NaCl(aq) + CO2(g) + H2O(l) How many moles are found in 15mL of 4.5M HCl? How many moles of CO2(g) will be produced when 15mL of 4.5M HCl completely reacts according to the reaction above? How many liters of CO2(g) will be produced when 15mL of 4.5M HCl completely reacts according to the reaction above at 25C at 1.05atm?Run 1 Run 2 Molarity of KMnO4 solution (M) from bottle 0.00101 0.00101 Initial reading of buret KMnO4 (mL) 0.62 11.35 Final reading of buret KMnO4 (mL) 11.33 21.70 Run 1 Run 2 Volume of KMnO4 solution (mL) Moles of MnO4- used for titration (mol) Moles of C2O42- in 100.0 mL of solution (mol) Molarity of C2O42- (M) Molarity of Cd2+ (M) Ksp of CdC2O4 Average Ksp of CdC2O4 Calculations: Moles of MnO4- used for titration of saturated solution CdC2O4 Moles of C2O42- in 100.0 mL of saturated solution of CdC2O4 Molarity of C2O42- in saturated solution of CdC2O4 Molarity of Cd2+ in saturated solution of CdC2O4 Solubility product, Ksp, of CdC2O4
- Will the calculated Molarity of NaOH be too high or too low or unaffected if the following happen: When you answer the question, consider how the situation affects the calculation of molarity of NaOH and moles NaOH, which is calculated from the mass of KHP. For each answer, you must supply a clear explanation for your answer. Often times, students will restate the facts rather than explaining why they chose the answer they chose. a) You add the weighed KHP to a flask containing a 60mL of water rather than 50 mL of water. Explain. Your answer must contain a well-thought-out and clearly written explanation. b) The buret is still wet with water on the inside when you add your NaOH solution. Explain c) The KHP is wet when you weigh it. Explain. d) You titrate past the equivalence point by 0.50mL Answer a-dIt is known that acid content has a major effect on theflavor of vinegars, but most cheaper vinegars are diluted similarly to 5% acidity Wt./vol. % is equivalent to gsolute per 100mL solution (so 5% is equivalent to 5 g acid/100 mL solution). a.) First, calculate the approximate molar concentration of acetic acid in the 5% wt./vol vinegar. b.) Next, calculate the expected molarity of acetic acid in the solution upon dilution by a factor of 5. Thank you!(1) Careless Carlie weighed her KHP sample, but forgot to bring her report sheet along, so she recorded the mass of KHP on a paper towel. During her titration, which required 18.46 mL of base, she spilled some base on her hands. She remembered to wash her hands, but forgot about the data on the towel, and used it to dry her hands. When she went to calculate the molarity of the base, Carlie discovered that she didn’t have the mass of her KHP. Her kindhearted instructor told Carlie that her base was 0.2987 M. Calculate the mass of Carlie’s KHP sample. Show calculations (2) What mass of solid NaOH would be needed to make 645 mL of Carlie’s NaOH solution? Show calculations.
- Hello. I am having issues understanding acetic acid and the correlation between its concentration and molarity. Can you help explain to me if the concentration and molarity of acetic acid in vinegar remains the same during its shelf life in the kithcen or does it change? I understand that it does not technically expire and it has an indefinite shelf life, but does the concentration and molarity change? If so, how. If it doesn't, why not? What is the molarity/concentration of acetic acid to begin with?? Thank you for your helpThe first goal is to make the oxalic acid standard solution. You measure 1.5232 g of oxalic acid on an analytical balance, add it to a 250-mL volumetric flask and add deionized H2O to a final volume of 250.0 mL. Molar mass of H2C2O4•2H2O = 126.07 g/mol Mass of H2C2O4•2H2O = 1.5232g what is the Number of moles of H2C2O4•2H2O?1) How much total glucose is present in a 75 Kg female person? (a normal person (70 kg BW) has approximately 43L body fluid).2) Please express the normal salt (NaCl) concentration in body fluid into molarity (mM).3) Commercial fuming Sulphuric acid (Oleum-H2S2O6) is 99.9% solution. Please convert it into molarity.4) Find out the Volume (dm3) of product (gas) at RTP when 0.58 M, 150 mL NaOH (aq.) reacts with 350 mL, 0.25 NH4Cl.5) The above reaction has the product Ammonia, which when dissolved in 650 mL ethanol makes an alkaline ethanolic solution. Find its molarity (M).6) Calculate the adult dose as per the BW of the baby. (Child dose-50 mg and the BW of the baby is 48 lb (British pound) (1lb=0.453 Kg)
- 10) How can you prepare 500 ml of 0.1M HCI, if the percentage is 35%, and density = 1.18g/ml, M.mass=36.5 g/molI’m so lost. How do I attempt this problem? I think I have to get NaC2H3O2 and MC2H3O2 in moles. And then combine the moles together for the A^- portion of the Henderson equation. But how do I do the rest?Kepone, a carcinogenic insecticide, fungicide, and larvicide for bananas, tobacco, and other domestic plants is insoluble in water. The US banned it's use in 1975, but the chemical is still used in some other countries. Before itsbanning, large amounts were depositing in the upper James River, posing a threat to the marine animals and groundwater supply. Most has settled into sands and sediments in the river.Kpis needing to be determined for a sediment sample. A solution of 0.02453 mg/L Kepone is prepared. 100.0 mL of solution is placed in a vial with 0.000100 kg of dry sediment. The sample is mixed for 3 days and the aqueous and solid phases are separated via filtration. The mass of Kepone in the aqueous phase is measured and the concentration is determined to be 0.02108 mg/L. The blank analysis shows no loss of Kepone to the vial walls. Determine the Kpusing the stepwise process outlinedbelow. Note, some of these may not becalculations, but rather givens from the problem. Total mass…