Data: Molar masses: MH = 1 g mol·l; Mo= 16 g mol- %3D Specific heat capacity at constant pressure: C, (H2O, 1) = 75.2 J mol-'K- %3D Standard molar enthalpy of melting of ice at 0 °C: AmeltH°(H2O) = 6.02 kJ mol- Standard molar enthalpy of vaporization of water at 100 °C: AvapH°(H2O) = 40.59 kJ mol One adds 180 g of ice and 90 g of liquid water at 0 °C (273.15 K) into a calorimeter. One then introduces in this calorimeter 54 g of water vapor at 100 °C by bubbling. - Conclude on the physical state of the water when the thermal equilibrium is achieved and calculate its temperature.
Data: Molar masses: MH = 1 g mol·l; Mo= 16 g mol- %3D Specific heat capacity at constant pressure: C, (H2O, 1) = 75.2 J mol-'K- %3D Standard molar enthalpy of melting of ice at 0 °C: AmeltH°(H2O) = 6.02 kJ mol- Standard molar enthalpy of vaporization of water at 100 °C: AvapH°(H2O) = 40.59 kJ mol One adds 180 g of ice and 90 g of liquid water at 0 °C (273.15 K) into a calorimeter. One then introduces in this calorimeter 54 g of water vapor at 100 °C by bubbling. - Conclude on the physical state of the water when the thermal equilibrium is achieved and calculate its temperature.
General Chemistry - Standalone book (MindTap Course List)
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Chapter18: Thermodynamics And Equilibrium
Section: Chapter Questions
Problem 18.98QP: When 1.000 g of ethylene glycol, C2H6O2, is burned at 25C and 1.00 atmosphere pressure, H2O(l) and...
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Transcribed Image Text:A calorimetric study
Data:
Molar masses:
MH = 1 g mol-; Mo= 16 g mol-
Specific heat capacity at constant pressure: Cp (H2O, 1) = 75.2 J mol·'K1
Standard molar enthalpy of melting of ice at 0 °C: AmeltH°(H2O) = 6.02 kJ mol·l
Standard molar enthalpy of vaporization of water at 100 °C: AvapH°(H2O) = 40.59 kJ mol-1
One adds 180 g of ice and 90 g of liquid water at 0 °C (273.15 K) into a calorimeter. One then
introduces in this calorimeter 54 g of water vapor at 100 °C by bubbling.
- Conclude on the physical state of the water when the thermal equilibrium is achieved and
calculate its temperature.
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