Calculate the enthalpy for this reaction: 2C(s) + H2(g) ---> C2H2(g) AH° = ??? kJ Given the following thermochemical equations: ΔΗ- %3D C2H2(g) + ½O2(g) ---> -1299.5 2CO2(g) + H2O(e) kJ ΔΗ' - C(s) + O2(g) ---> CO2(g) -393.5 kJ H2{g) + ½O2{g) -- AH° = ---- H20(e) -285.8 kJ

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section5.5: Enthalpy Changes For Chemical Reactions
Problem 1RC: 1. For the reaction 2 Hg(l) + O2(g) → 2 HgO(s), ∆rH° = 181.6 kJ/mol-rxn. What is the enthalpy change...
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Calculate the enthalpy for this reaction:
2C(s) + H2(g) ---> C2H2(g)
AH° = ??? kJ
Given the following thermochemical equations:
C2H2(g) + 5/202(g) ---> 2CO2(g) + H20(e)
C(s) + 02(g) ---> CO2(g)
H2(g) + 1/202(g) H20(e)

please review picture different set up. 

Calculate the enthalpy for this reaction:
2C(s) + H2(g) --->
AH° = ???
C2H2(g)
kJ
Given the following thermochemical
equations:
ΔΗ'
%D
C2H2[g) + ½O2{g)-
2CO2(g) + H20(e)
- --
-1299.5
kJ
ΔΗ-
%D
C(s) + O2(g) ---> CO2(g)
-393.5 kJ
H2(g) + ½O2(g) --->
ΔΗ :
H20(e)
-285.8 kJ
Transcribed Image Text:Calculate the enthalpy for this reaction: 2C(s) + H2(g) ---> AH° = ??? C2H2(g) kJ Given the following thermochemical equations: ΔΗ' %D C2H2[g) + ½O2{g)- 2CO2(g) + H20(e) - -- -1299.5 kJ ΔΗ- %D C(s) + O2(g) ---> CO2(g) -393.5 kJ H2(g) + ½O2(g) ---> ΔΗ : H20(e) -285.8 kJ
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