Decode the message ACXUT CXRT, which was encrypted using the congruence c ≡ (3p + 5) mod 26 that corresponds to the previous table (cyclical English alphabet. Write the plaintext on the space provided below. 24121426the corresponding letter in the ciphertext message is given by;ugC IIIIII positions, thenc = (p + m)mod 26where c is the encrypted code, p is the number corresponds to a letter in an English alphabetin a normal position, m is the shifted position and n = 26 is the modulus since there are 26letters in an English alphabet.TableCyclical English AlphabetabdeFikmqp.16uV13.810111213 1415171819 202122 23 24 25 0-9-8-7-6-5-4-3-2-1252322 212019181716151413 121110Note that the letter Z is coded as zero because 26 = 0 mod 26.185

Given c≡3p+5mod 26 Give cipher text is ACXUT CXRT To find the plain text: First solve the given…

Decode the message ACXUT CXRT, which was encrypted using the congruence c ≡ (3p + 5) mod 26 that corresponds to the previous table (cyclical English alphabet. Write the plaintext on the space provided below.

Decode the message ACXUT CXRT, which was encrypted using the congruence c ≡ (3p + 5) mod 26 that corresponds to the previous table (cyclical English alphabet. Write the plaintext on the space provided below.

Elements Of Modern Algebra

8th Edition

ISBN:9781285463230

Author:Gilbert, Linda, Jimmie

Publisher:Gilbert, Linda, Jimmie

Chapter2: The Integers

Section2.7: Introduction To Coding Theory (optional)

Problem 12E: Suppose that the check digit is computed as described in Example . Prove that transposition errors...

See similar textbooks

Related questions

Q: Decrypt the message XUPPWFIDD which was encrypted using the athine cipher f(p) = (15p + 6) mod 26…

Q: Consider the linear congruential number generator given by n + (ахр-1 + с) mod m

A: In this question, we have given a linear congruential generator xn←axn-1+c mod(m)Given thata=4,…

Q: Decrypt the message ORWWPGDII which was encrypted using the affine cipher: f(p) = (11p + 5) mod 26…

Q: (a) Solve the linear congruence 26x = 1 modulo 33

A: Solution

Q: Without using Calculator or other mechanical tools, find the Decryption function of the following…

A: Given encryption function is : fp=7p+3 mod26

Q: Suppose p = 5 and q RSA cryptosystem with public key (n, e) = (55, 7)? 11. Which of the following is…

Q: Encode the message MATH using the coding formula C=(7P +11)mod 26.

A: The solution is given as follows

Q: 5. Decrypt these messages encrypted using the shift cipher f(p) = (p + 10) mod 26. a) CEBBOXNOB XYG…

A: The Caesar Cipher is a type of shift cipher. Shift Ciphers work by using the modulo operator to…

Q: The message, FMULMZV, is an encrypted message using the affine cipher f (p) = (11p - 6) mod 26. Find…

Q: (Adapted from Richardson problem Solve the congruence 589z = 494 (mod 817). Hint: The solution…

Q: Find d the inverse of 43 mod 6602

A: we use Euclidean algorithm to find the inverse of 43 mod 660.

Q: (Adapted from Richardson problem 4.2.2, Solve the congruence 589.r = 494 (mod 817). Hint: The…

Q: C. Determine whether each linear congruence is solvable. 1. 12x=18 (mod 16) 2. 15y =18 (mod 12)…

Q: Solve the linear congruence 10x ≡ 15 (mod 45).

Q: Encrypt the message ATTACK using c = (p+12) mod 26 O a. MGGMOX O b. LFFLOW O C. LFFLOX O d. MFFMOW

A: Each letter in the alphabet corresponds to a number between 0 to 26. Letter A B C D E F G H I J K…

Q: By doing direct enumeration, find the period of the following congruential generator: Xj+1=11X; mod…

Q: Q7. Solve the following set of simultaneous congruences. 4x = 1(mod 5) 6x = 5(mod 11) 2x = 5(mod 13)

Q: encryted using a shift cipher with C(x) = (P(x) – 12)( mod 26). Decrypt the The Ciphertext below was…

A: The given encrypt function is Cx=Px-12 mod 26. Decrypt the chiphertext XIZWIGQOSGOF. From the…

Q: Encrypt the message ATTACK using the RSA system with n = 43 · 59 and e = 13, translating each letter…

Q: In the use of RSA Cryptography, for the public key (11, 65), what is the decrypted original message…

A: Solution :-

Q: Decode the message IGHT OHGG, which was encrypted using the congruence c= (7p + 1) mod 26.

Q: Determine the cycle or lifetime (N) of the following congruential generator. Xi+1 = (13Xi + 9) mod…

A: Generally linear Congruantial generator is given as, Xi+1 = (aXi + c ) mod m Then it has period or…

Q: C. Determine whether each linear congruence is solvable. 4.276y=3476 (mod 1276) 5. x = 3 (mod 9) 6.…

Q: Decrypt the message ''EOXH MHDQV Using the shift cipher f(p)=(p+3)mod26

A: Solution by using shift cipher as follows :

Q: a. Find the inverse of 31 modulo 73 b. Decrypt the following message using shift cipher: f(p) = (p+…

A: The inverse of 31 modulo 73 .

Q: Solve the following linear congruence: 36x = 8 (mod 102).

A: The linear congruence ax ≅b(mod m) has a solution iff d|b where d=(a, m)

Q: Find integers X, E > 2 such that XE = X (mod 74329). How does this illustrate a potential problem in…

A: Given : E ≥ 2 such that XE ≡ X (mod 74329). To find integer X.

Q: Decrypt the message "XMJQYJWNSUQFHJ" which was encrypted with a Caesar cipher with a shift of 5 (A…

A: To decode code "XMJQYJWNSUQFHJ" using Caesar cipher with a shift of 5.

Q: Suppose that the most common letter and the second most common letter in a long ciphertext produced…

Q: Use this theorem to solve the following congruences: (1) x° = 2 mod 35 (2) x' = 13 mod 35

A: Since you have asked multiple questions, we can solve first question for you. If you want other…

Q: The ISBN of a book is a unique 13-digit code', also known as ISBN-13, that encodes information about…

A: ISBN: 978-0-75664-979-1 The congruence relation is…

Q: Solve the following system of congruencEs. = 1 (mod 999) = 2 (mod 1001) = 3 (mod 1003) = 4 (mod…

A: Given, x≡1mod 999....(1)x≡2mod 1001...(2)x≡3mod 1003...(3)x≡4mod 1004...(4)x≡5mod 1007...(5) We…

Q: Decrypt the message "WFLRV" which is encrypted by the encryption function f (p) = (3p + 11) mod 26.…

A: Given: Encryption function is f(p)=3p+11mod26. Encrypted message is "WFLRV". For W, P=22.…

Q: Decrypt these messages encrypted using the shift cipher f (p) = (p + 10) mod 26.a) CEBBOXNOB XYGb)…

Q: 1 Solve the following system of congruences X= 2 (mod 3) x = 3 (mod 5) X= 2 (mod 7)

Q: Q7. Solve the following set of simultaneous congruences. 6x = 1(mod 5) 5x = 3(mod 11) 2x = 5(mod 13)

Q: Show complete solution. Decode the message LOFT JGMK LBS MNWMK that was encrypted using the…

A: From the given congruence formula c=3p+4 c-4=3p Multiplying both sides of the above equation with 9…

Q: Find the first few terms of the sequence of pseudorandom numbers generated using the linear…

A: We have to find few terms of the given sequences.

Q: Solve the following linear congruence. 36x = 8 (mod 102).

A: On solving ,we get

Q: 1. Express the greatest common divisor of 197 and 13, as a linear combination of 197 and 13. 2.…

A: Since you have asked for a multiple question, we will solve the first question for you if you want…

Q: Find the inverse of the congruence 6x = 1 (mod 29) using Euclidean algorithm.

Q: Apply the affine cipher formula C=(5P + 2) mod 26 to encript "LASER PRINTER". JGNSA DUNTXNA JSNAS…

Q: Solve the following congruences. a) 5x = 1 (mod 13) b) 12x = 40 (mod 88)

A: Given: To explain the given statement as follows, We need to solve the following congruences 5(x) =…

Q: Use the cipher: f(x) = (x + 10) mod 26,0 ≤ x ≤5 to decrypt "SD SC XYD PKSB".

A: To Use: The cipher: f(x) = (x + 10) mod 26, 0≤x≤25 to decrypt "SD SC XYD PKSB".

Q: Find all pairs of integers keys (a, b) for affine ciphers for which the encryption function c = (ap…

Q: Use the RSA cipher with public key (n, e) = (713, 43) to encrypt the word "TEE." Start by encoding…

Q: The ciphertext letter for T when the congruence is C =( P + 10 ) mod 26 is

Q: The linear congruence 8x = 16(mod14) is solvable. False True

Q: Suppose that when a string of English text is encrypted using a shift cipher f (p) = (p + k) mod 26,…

Question

24
12
14
26
the corresponding letter in the ciphertext message is given by;
ugC III
III positions, then
c = (p + m)mod 26
where c is the encrypted code, p is the number corresponds to a letter in an English alphabet
in a normal position, m is the shifted position and n = 26 is the modulus since there are 26
letters in an English alphabet.
Table
Cyclical English Alphabet
a
b
d
e
F
i
k
m
q
p.
16
u
V
1
3.
8
10
11
12
13 14
15
17
18
19 20
21
22 23 24 25 0
-9
-8
-7
-6
-5
-4
-3
-2
-1
25
23
22 21
20
19
18
17
16
15
14
13 12
11
10
Note that the letter Z is coded as zero because 26 = 0 mod 26.
185

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Searching and Sorting$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, advanced-math and related others by exploring similar questions and additional content below.

Similar questions

Suppose that the check digit is computed as described in Example . Prove that transposition errors of adjacent digits will not be detected unless one of the digits is the check digit. Example Using Check Digits Many companies use check digits for security purposes or for error detection. For example, an the digit may be appended to a -bit identification number to obtain the -digit invoice number of the form where the th bit, , is the check digit, computed as . If congruence modulo is used, then the check digit for an identification number . Thus the complete correct invoice number would appear as . If the invoice number were used instead and checked, an error would be detected, since .
Rework Example 5 by breaking the message into two-digit blocks instead of three-digit blocks. What is the enciphered message using the two-digit blocks? Example 5: RSA Public Key Cryptosystem We first choose two primes (which are to be kept secret): p=17, and q=43. Then we compute m (which is to be made public): m=pq=1743=731. Next we choose e (to be made public), where e must be relatively prime to (p1)(q1)=1642=672. Suppose we take e=205. The Euclidean Algorithm can be used to verify that (205,672)=1. Then d is determined by the equation 1=205dmod672 Using the Euclidean Algorithm, we find d=613 (which is kept secret). The mapping f:AA, where A=0,1,2,...,730, defined by f(x)=x205mod731 is used to encrypt a message. Then the inverse mapping g:AA, defined by g(x)=x613mod731 can be used to recover the original message. Using the 27-letter alphabet as in Examples 2 and 3, the plaintext message no problem is translated into the message as follows: plaintext:noproblemmessage:13142615171401110412 The message becomes 13142615171401110412. This message must be broken into blocks mi, each of which is contained in A. If we choose three-digit blocks, each block mim=731. mi:13142615171401110412f(mi)=mi205mod731=ci:082715376459551593320 The enciphered message becomes 082715376459551593320 where we choose to report each ci with three digits by appending any leading zeros as necessary. To decipher the message, one must know the secret key d=613 and apply the inverse mapping g to each enciphered message block ci=f(mi): ci:082715376459551593320g(ci)=ci613mod731:13142615171401110412 Finally, by re-breaking the message back into two-digit blocks, one can translate it back into plaintext. Three-digitblockmessage:13142615171401110412Two-digitblockmessage:13142615171401110412Plaintext:noproblem The RSA Public Key Cipher is an example of an exponentiation cipher.
Using y=2x-1 (mod26), 1. encode GGWP 2. decode IY
An encryption function is given as f(p) = (p + 3) mod 26 where p is the position of the input letter in English alphabets and f(p) is the position of the encrypted alphabet. Find the encrypted representation of “STOP”. A new airline company wants to operate non-stop (two-way) flights between 33 major cities. What is the total number of flights the company needs for this operation?
1. Express the greatest common divisor of 197 and 13, as a linear combination of 197 and 13. 2. Decrypt these messages encrypted using the Caesar cipher. VLR DLQ QEFP 3. Decide whether each of these integers is congruent to 5 modulo 17. (justify your answer) a) 80 b) 103 c) -29 d) -122
Encrypt this plaintext using Decimation Cipher with key of 3 (Use the attached photo as reference) plaintext: M A J O R