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- Sample: Commercial bleach Technical specifications:- Composition: sodium hypochlorite (NaClO) and demineralized water;- Active chlorine content: 2.00 to 2.50% (m/m);- Active ingredient: sodium hypochlorite (NaClO).- Approximate density: 1.08 g/ml;- Physical Aspect: Liquid;- Color: Colorless. Note: the active chlorine content refers to the chlorine gas produced from the following reaction:ClO¯ + Cl¯ + 2H+ ⇋ Cl₂(g) + H₂OData:M.A.: H = 1.0079 g/mol; Na = 22.989769 g/mol; S = 32.065 g/mol; I = 126.90447 g/mol; O = 15.9994 g/mol; Cl = 35.453 g/mol. Material available in the laboratory's warehouse: Reagents:Distilled water; standardized solution of sodium thiosulfate (Na₂S₂O₃), at a concentration of 0.0500 mols/L; 20% KI solution; glacial acetic acid and; starch gum (indicator). Glassware:Bechers of all sizes available on the market; 50, 100, 150, 200 and 250 ml Erlenmeyer flasks; 10.00 and 25.00 mL volumetric pipettes; 25.00 mL burette; 25.00, 50.00 and 100.0 mL volumetric flasks. Calculate…A solution was made by dissolving 9.0g of hydrated aluminium sulphate Al2(SO)3 in 250cm3 of solution. (R.A.M: Al = 27, O = 16, S = 32, H = 1) Calculate the number of moles of hydrated aluminium sulphate solution the number of moles of sulphate ions in this solution the concentration (moldm-3) of the hydrated aluminium sulphateThe ideal product of gravimetric analysis called precipitate should portray some specific properties. Which among the following is a property of a good precipitate and why?
- The concentration of CO in air is determined by passing a known volume of air through a tube that contains I2O5, forming CO2and I2. The I2 is removed from the tube by distilling it into a solution that contains an excess of KI, producing I3-. The I3-is titrated with a standard solution of Na2S2O3. In a typical analysis a 4.79-L sample of air is sampled as described here, requiring 7.17 mL of 0.00329 M Na2S2O3 to reach the end point. If the air has a density of 1.23 × 10–3 g/mL, determine the parts per million CO in the airNitrous acid (HNO2) disproportionates in acidic solutionto nitrate ion (NO3- ) and nitrogen oxide (NO). Write abalanced equation for this reaction.The following reactions (note that the arrows are pointingonly one direction) can be used to prepare an activity seriesfor the halogens:Br2(aq) + 2 NaI(aq)----->2 NaBr(aq) + I2(aq)Cl2(aq) + 2 NaBr(aq)----->2 NaCl(aq) + Br2(aq)(a) Which elemental halogen would you predict is the moststable, upon mixing with other halides? (b) Predict whethera reaction will occur when elemental chlorine and potassiumiodide are mixed. (c) Predict whether a reaction will occurwhen elemental bromine and lithium chloride are mixed.
- Give the summary of reaction and rationalization of each samples.25 mL of a bleach (NaOCl) sample is diluted to 500 mL. An excessive amount of KI is added to the 20 mL solution taken from here, and the released I2 is titrated with 35.5 mL of 0.0409 M NaS2O3. Accordingly, calculate the weight percent by volume of NaOCl in the sample.(MaNaOC:74,4 g/mol)0.1724g of a mineral containing MnO₂ was dissolved and then treated with excess iodide according to the following unbalanced reaction: MnO2(s) + H+ → Mn²+ + I2 + H₂O The I₂ released was titrated with a solution of Na₂S2O3 0.07320 mol/L, requiring 14.65 mL to reach the point end of degree a) Determine the percentage of MnO₂ in the ore. b) When iodine solutions are used as titrants these are prepared by dissolving 1₂ in concentrated KI. Explain the reason for the need for KI in the preparation of these solutions?
- the reaction below takes place in an aqueous basic solution MnO2 + Fe ^3+ ---->Fe^2+ + MnO4- when balanced, the smallest whole number coefficient for OH- is?explain it properly both mustAn ore containing Fe3O4 was analyzed by dissolving a 1.5419-g sample in concentrated HCl. HNO3 was then added to oxidize any Fe2+ to Fe3+. The Fe3+ was precipitated as Fe(OH)3 by adding NH3. The precipitate was collected by filtration and was finally heated yielding 0.8525 g of Fe2O3. Report the concentration of Fe3O4 in the sample as %(w/w). (Note: the final answer is said to be 53.4%)