Implement the build_dictionary() function to build a word frequency dictionary from a list of words. Ex: If the words list is: ["hey", "hi", "Mark", "hi", "mark"] the dictionary returned from calling build_dictionary(words) is: {'hey': 1, 'hi': 2, 'Mark': 1, 'mark': 1} half answered: code: def build_dictionary(words): # The frequencies dictionary will be built with your code below. # Each key is a word string and the corresponding value is an integer # indicating that word's frequenc # The following code asks for input, splits the input into a word list, # calls build_dictionary(), and displays the contents sorted by key. if __name__ == '__main__': words = input().split() your_dictionary = build_dictionary(words) sorted_keys = sorted(your_dictionary.keys()) for key in sorted_keys: print(key + ': ' + str(your_dictionary[key

Implement the build_dictionary() function to build a word frequency dictionary from a list of words. Ex: If the words list is: ["hey", "hi", "Mark", "hi", "mark"] the dictionary returned from calling build_dictionary(words) is: {'hey': 1, 'hi': 2, 'Mark': 1, 'mark': 1} half answered: code: def build_dictionary(words): # The frequencies dictionary will be built with your code below. # Each key is a word string and the corresponding value is an integer # indicating that word's frequenc # The following code asks for input, splits the input into a word list, # calls build_dictionary(), and displays the contents sorted by key. if name == 'main': words = input().split() your_dictionary = build_dictionary(words) sorted_keys = sorted(your_dictionary.keys()) for key in sorted_keys: print(key + ': ' + str(your_dictionary[key

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter17: Linked Lists

Section: Chapter Questions

Problem 18SA

See similar textbooks

Word frequencies (dictionaries)

Implement the build_dictionary() function to build a word frequency dictionary from a list of words.

Ex: If the words list is:

["hey", "hi", "Mark", "hi", "mark"]

the dictionary returned from calling build_dictionary(words) is:

{'hey': 1, 'hi': 2, 'Mark': 1, 'mark': 1}

half answered:

code:

def build_dictionary(words):
# The frequencies dictionary will be built with your code below.
# Each key is a word string and the corresponding value is an integer
# indicating that word's frequenc

# The following code asks for input, splits the input into a word list,
# calls build_dictionary(), and displays the contents sorted by key.
if __name__ == '__main__':
words = input().split()
your_dictionary = build_dictionary(words)
sorted_keys = sorted(your_dictionary.keys())
for key in sorted_keys:
print(key + ': ' + str(your_dictionary[key]))

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