def crop_map (m: list[list[int]], corner_1: tuple[int, int], corner 2: tuple[int, int]) -> list[list[int]]: Given a 2D representation of an elevation map and two points on the ma and , crop the map and return the smallest map such that both these coordinates are now a corner on the new map. Note that the new cropped map could just be a row, a column, or even a single square like [[1]]. The new map must remain rectangular, that is, each of its rows must be equal in length. Do not modify the original map. >>> sample_map = [[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]] >>> cгоp_mаp(sample_map, (1, 1), (2, 2)) [[6, 7], [10, 11]] >>> crop_map (sample_map, (0, 0), (3, 0)) [[1], [5], [9], [13]] >>> crop_map (sample_map, (0, 3), (0, 0)) [[1, 2, 3, 4]] pass

def crop_map (m: list[list[int]], corner_1: tuple[int, int], corner 2: tuple[int, int]) -> list[list[int]]: Given a 2D representation of an elevation map and two points on the ma and , crop the map and return the smallest map such that both these coordinates are now a corner on the new map. Note that the new cropped map could just be a row, a column, or even a single square like [[1]]. The new map must remain rectangular, that is, each of its rows must be equal in length. Do not modify the original map. >>> sample_map = [[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]] >>> cгоp_mаp(sample_map, (1, 1), (2, 2)) [[6, 7], [10, 11]] >>> crop_map (sample_map, (0, 0), (3, 0)) [[1], [5], [9], [13]] >>> crop_map (sample_map, (0, 3), (0, 0)) [[1, 2, 3, 4]] pass

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter17: Linked Lists

Section: Chapter Questions

Problem 5PE

See similar textbooks

Similar questions

import java.util.ArrayList;import java.util.Arrays;public class PS{/*** Write the method named mesh.** Start with two ArrayLists of String, A and B, each with* its elements in alphabetical order and without any duplicates.* Return a new list containing the first N elements from the two* lists. The result list should be in alphabetical order and without* duplicates. A and B will both have a size which is N or more.* Your solution should make a single pass over A and B, taking* advantage of the fact that they are in alphabetical order,* copying elements directly to the new list.** Remember, to see if one String is "greater than" or "less than"* another, you need to use the compareTo() method, not the < or >* operators.** Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]** @param a an ArrayList of String in alphabetical order.* @param b an…
2 //please write it in java This is a circular doubly linked list. It starts at the head pointer (Head). Write a function that adds a node (P) at the nth location away from the Head keeping the circle connected. For example, based on the image, the list is: C, D, B, A After calling addNthNode(Head, P, 2), the list becomes C, F, D, B, A Note that if the position is 1 then the Head should be updated. Your code should validate parameters, and handle edge cases. void addNthNode (Node Head, Node P, int position){ // your code goes here }
in java language import java.util.ArrayList;import java.util.Arrays; Write the method named mesh.* * Start with two ArrayLists of String, A and B, each with * its elements in alphabetical order and without any duplicates. * Return a new list containing the first N elements from the two * lists. The result list should be in alphabetical order and without * duplicates. A and B will both have a size which is N or more. * Your solution should make a single pass over A and B, taking * advantage of the fact that they are in alphabetical order, * copying elements directly to the new list.* * Remember, to see if one String is "greater than" or "less than" * another, you need to use the compareTo() method, not the < or > * operators. * * Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]* * @param a an ArrayList of String in alphabetical order.*…
Implement a program that creates an unsorted list by using a linked list implemented by yourself. NOT allowed to use LinkedList class or any other classes that offers list functions. It is REQUIRED to use an ItemType class and a NodeType struct to solve this. Use C++! The “data.txt” file has three lines of data 100, 110, 120, 130, 140, 150, 160 100, 130, 160 1@0, 2@3, 3@END You need to create an empty unsorted list add the numbers from the first line to list using putItem() function. Then print all the current keys to command line in one line using printAll(). delete the numbers given by the second line in the list by using deleteItem() function. Then print all the current keys to command line in one line using printAll().. putItem () the numbers in the third line of the data file to the corresponding location in The list. For example, 1@0 means adding number 1 at position 0 of the list. Then print all the current keys to command line in one line…
There’s a somewhat imperfect analogy between a linked list and a railroad train, where individual cars represent links. Imagine how you would carry out various linked list operations, such as those implemented by the member functions insertFirst(), removeFirst(), and remove(int key) from the LinkList class in this hour. Also implement an insertAfter() function. You’ll need some sidings and switches. You can use a model train set if you have one. Otherwise, try drawing tracks on a piece of paper and using business cards for train cars.
Q4 Suppose, alist is a 2-dimensional list that is defined as follows. alist = [ [1], [2,3], [5,6,7] ] Which is the best option to access the last element of the last element of this list (i.e., 7)? Question 4 options: alist[ len(alist) - 1 ][len(alist[len(alist) - 1]) - 1] alist[ len(alist) - 1 ][len(alist[len(alist) - 1])] alist[3][3] alist[ len(alist) - 1 ][1]
For this assignment, you need to implement link-based List and derivative ADTs in Java. To complete this, you will need the following: A LinkNode structure or class which will have two attributes - a data attribute and a pointer attribute to the next node. The data attribute of the LinkNode should be the Money class of Lab 1. A Singly Linked List class which will be composed of three attributes - a count attribute, a LinkedNode pointer/reference attribute pointing to the start of the list and a LinkedNode pointer/reference attribute pointing to the end of the list. Since this is a class, make sure all these attributes are private. The attribute names for the Node and Linked List are the words in bold in #1 and #2. For the Linked List, implement the most common linked-list behaviors as explained in class - getters/setters/constructors/destructors for the attributes of the class, (a) create new list, (b) add data, (c) delete data, (d) find data, (e) count of data items in the…
Add a new public member function to the LinkedList class named reverse() which reverses the items in the list. You must take advantage of the doubly-linked list structure to do this efficiently as discussed in the videos/pdfs, i.e. swap each node’s prev/next pointers, and finally swap headPtr/tailPtr. Demonstrate your function works by creating a sample list of a few entries in main(), printing out the contents of the list, reversing the list, and then printing out the contents of the list again to show that the list has been reversed. Note: your function must actually reverse the items in the doubly-linked list, not just print them out in reverse order! Note: we won't use the copy constructor in this assignment, and as such you aren't required to update the copy constructor to work with a doubly-linked list. This is what I have so far but its not working! template<class ItemType>void LinkedList<ItemType>::reverse(){ Node<ItemType>*curPtr,*prev,*next;…
Using java, write an easier version of a linked list with only a couple of the normal linked list functions and the ability to generate and utilize a list of ints. The data type of the connection to the following node can be just Node, and the data element can be just an int. You will need a reference like (Java) or either a reference to the first node, as well as one to the last node. (Answer the following questions) 1) Create a method or function that accepts an integer, constructs a node with that integer as its data value, and then includes the node to the end of the list. If the new node is the first one, this function will also need to update the reference to the first node. This function will need to update the reference to the final node. Consider how to insert the new node following the previous last node, and keep in mind that the next reference for the list's last node should be null. 2) Create a different method or function that iteratively explores the list, printing…
Add a proper function to the following linked list that will copy all elements with value above average into another list , then apply it to the list created in main function and print your resultant list. Example: l.copy(l2); will copy all elements with value greater than average into l2 #include <iostream> using namespace std; struct node { int data; node *next,*prev; node(int d,node *p=0,node *n=0) { data=d; prev=p; next=n; } }; class list { node *head; public: list(); void print(); void add_end(int el); }; list::list() { head=0; } void list::add_end(int el) { if(head==0) head=new node(el); else { node *t=head; for(;t->next!=0;t=t->next); t->next=new node(el,t); } } void list::print() { for(node *t=head;t!=0;t=t->next) cout<<t->data<<" "; cout<<endl; } void main() { list l; l.add_end(7); l.add_end(3); l.add_end(9);…
Consider the following implementation of the node and doubly linked-list: Extend the class doubly_linked_list by adding the following methods: *Largest method .This method should return the largest element in a doubly linked-list. *Delete method. This method should delete the first occurrence of an element (value) from a doubly linked-list. USE C++ PLEASE THE CODE : template <class type> class node{public:type info;node<type> * next;// nextnode<type> * prev;//back }; template <class type>class doubly_linked_list {//data membersprivate:node<type> *head, *tail;int length;public:doubly_linked_list(){head = tail = NULL;length = 0;}bool isEmpty(){ // return (head==NULL);if (head == NULL)return true;elsereturn false;} void Append(type e){node<type> *newnode = new node<type>;newnode->info = e;if (isEmpty()){newnode->next = NULL;newnode->prev = NULL;head = newnode;tail = newnode;}else{tail->next = newnode;newnode->prev =…
Create a template class for a dynamic 1D array. You can model your class off of our Stringclass or the dynamic list class. Changes from Stringclass: You won't need an end-of-string element in the array. The element type is now templated. Translation will no longer be necessary. operators - and -= 'might' now make sense (erase element(s)?). ... Show how useful your template array class is by creating arrays of short integers doubles Stringclass objects (static) Pointclass objects pointers to Pointclass objects (each allocated on the heap) — all in one test application. Make sure your test application is a good/thorough test of your class. (Your test application might utilize the applyand accumulatefunctions from lecture to facilitate testing. Also note how a typical template test application is structured — using templates to ease development.