Describe how the current flowing through the resistor varied as the voltage was increased?Based on the graph, What do the slopes of the best fit lines represent? Explain Do you consider the resistor as ohmic? Why or why not? • CURRENT TRIAL 1- CURRENT TRIAL 2A CURRENT TRIAL 3x CURRENT TRIAL 4* CURRENT TRIALS-Linear (CURRENT TRIAL 1)Linear (CURRENT TRIAL 2)-- Linear (CURRENT TRIAL 3)-Linear (CURRENT TRIAL 4)- Linear (CURRENT TRIAL 5)2.2Current trial 1Current trial 22y- 0.2017x - 0.0173R* = 0.9991y= 0.2035x - 0.0253R0.99961.81.6Current trial 4Current trial 3y=0.2025x - 0.01671.4v=0.2025x - 0.024R =0.9993R = 0.99891.2Current trial 5y= 0.2027x - 0.0240.8R 0.99860.60.40.2248.1012VOLTAGECURRENT

1)As the voltage is increased in the circuit we see from the graph that the current is also…

Describe how the current flowing through the resistor varied as the voltage was increased? Based on the graph, What do the slopes of the best fit lines represent? Explain Do you consider the resistor as ohmic? Why or why not?

Describe how the current flowing through the resistor varied as the voltage was increased? Based on the graph, What do the slopes of the best fit lines represent? Explain Do you consider the resistor as ohmic? Why or why not?

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter14: Heat And Heat Transfer Methods

Section: Chapter Questions

Problem 68PE: Integrated Concepts Frozen waste from airplane toilets has sometimes been accidentally ejected at...

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Question

Describe how the current flowing through the resistor varied as the voltage was increased?
Based on the graph, What do the slopes of the best fit lines represent? Explain
Do you consider the resistor as ohmic? Why or why not?

• CURRENT TRIAL 1
- CURRENT TRIAL 2
A CURRENT TRIAL 3
x CURRENT TRIAL 4
* CURRENT TRIALS
-Linear (CURRENT TRIAL 1)
Linear (CURRENT TRIAL 2)-
- Linear (CURRENT TRIAL 3)
-Linear (CURRENT TRIAL 4)
- Linear (CURRENT TRIAL 5)
2.2
Current trial 1
Current trial 2
2
y- 0.2017x - 0.0173
R* = 0.9991
y= 0.2035x - 0.0253
R0.9996
1.8
1.6
Current trial 4
Current trial 3
y=0.2025x - 0.0167
1.4
v=0.2025x - 0.024
R =0.9993
R = 0.9989
1.2
Current trial 5
y= 0.2027x - 0.024
0.8
R 0.9986
0.6
0.4
0.2
2
4
8.
10
12
VOLTAGE
CURRENT

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