Determination of the Universal Gas Constant Postlab 1. An evaluation of Rwas performed using the procedures outlined in this exercise, The barometric pressure was 735 torr and the temperature was 21.5 "C. The volume of H2(g) collected was 32.7 mL. The calculated value of Rwas 0.0817 L-atm/mol-K. a. How many grams of Mg metal were used in this determination? 0.0316 b. If the correction for the vapor pressure of water had not been performed, what would be the calculated value of R? 70.361 Incorrect c. If the syringe volume had been incorrectly read, resulting in a calculated H, volume of 30.6 ml, what would be the percent error in the calculated value of Rwith respect to the originally calculated value (0.0817 L-atm/mol-K)? 6.4 %
Determination of the Universal Gas Constant Postlab 1. An evaluation of Rwas performed using the procedures outlined in this exercise, The barometric pressure was 735 torr and the temperature was 21.5 "C. The volume of H2(g) collected was 32.7 mL. The calculated value of Rwas 0.0817 L-atm/mol-K. a. How many grams of Mg metal were used in this determination? 0.0316 b. If the correction for the vapor pressure of water had not been performed, what would be the calculated value of R? 70.361 Incorrect c. If the syringe volume had been incorrectly read, resulting in a calculated H, volume of 30.6 ml, what would be the percent error in the calculated value of Rwith respect to the originally calculated value (0.0817 L-atm/mol-K)? 6.4 %
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter5: The Gaseous State
Section: Chapter Questions
Problem 5.127QP: A 1.000-g sample of an unknown gas at 0C gives the following data: P(atm) V (L) 0.2500 3.1908 0.5000...
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