Determine the group index of the soil sample no. 6.Sieve analysis(percent finer)SoilLiquidPlasticityNo.No. 4No. 200limitlimit1943NP10077632510010038655284453622592483086040264799766032Select one:а. 5b. 7c. 3d. none of the choicese. 0

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Answered: Determine the group index of the soil…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The given data sohws a sieve analysis of a soild sample. Classify the soild using AASHTO Method. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 96 No. 8 2.380 80 No. 10 2.000 78 No.20 0.840 61 No.40 0.420 56 No. 60 0.250 48 No. 100 0.150 39 No. 200 0.075 33 Characteristics of No. 40 Fraction LL 46 PL 31
A 500g (assume no wastes) of dry soil was used for a soil mechanical analysis. Themass of soil retained in each sieve, and hydrometer analysis data are given in Table 1and Table 2, respectively.Table 1. Sieve Analysis DataUS SieveDiameter Mass Ret., g2.00 mm 101.40 mm 20500 μm 135150 μm 60250 μm 145850 μm 6075 μm 45 Particle PercentDiameter Passing, %20 μm 2.510 μm 1.52 μm 11. What is the value of the percent passing for sieve with 2 mm. opening inpercentage?2.What is the value of the percent passing for sieve with 150 μm. opening inpercentage?3.What is the value of the coefficient of uniformity?4.What are the percentages of gravel, sand, and Fines using the limits indicated byUSCS?5.What are the percentages of gravel,…
Sieve # Maas retained (gr) 4 0 10 11,5 16 11,7 20 12 30 12,9 40 17,8 50 19,1 70 35,1 100 38,1 200 118 Pan 335 Draw grain size distribution curve,find D60, D30, D10 Classify the soil
PLS ANSWER ASAPA WET OF SOIL SAMPLE HAS A VOLUME OF 4.85 x 10^-4 m3 AND WEIGHS 8.5N. AFTER OVEN DRYING, THE WEIGHT REDUCES TO 7.5N. IF sg = 2.7DETERMINE THE UNIT WEIGHT. DETERMINE THE MOISTURE CONTENT. DETERMINE THE DEGREE OF SATURATIONAnswer in 4 decimal places with unit
1. Classify the following soils using USCS givegroup symbol and group name.a) A 55% of soil sample retained in sieve no. 4and 89% retained on sieve no. 200. The soilsample has a liquid limit = 28% and plasticLimit = 18% Cu = 4.2, Cc = 1.4 2. A saturated soil has the followingcharacteristics:Initial Volume = 25 cm3Final Volume = 16 cm3Mass of wet soil = 45 gMass of dry soil = 31 ga) Determine the Shrinkage Limitb) Determine the Shrinkage Ratioc) Determine the Specific Gravity of the soil
GEOTECHNICAL ENGINEERING: The resuts of a sieve analysis for a soil sample are given in the Table. Cc = 0.5 and Cu = 5. If the LL and the PL of the soil sample are 55 and 40 respectively, classify the soil according to USCS classification. Sieve Opening (mm) % passing 4.75 45 0.075 9
For a soil, given e= 0.75, w= 22%, Gs= 2.66, calculate the dry density of soil in slug/ft3. Note ρ of water= 1.94 slug/ft3 a. 3.8 b. 2.95 c. 3.6 d. 2.85 With fbd if necessary
soil mechanic. Classify the soil according to unified soil classification system USCS; if the following data is given : Passing sieve No. 200 =7% / Passing sieve No. 4 = 40% / D10= 0.18, D30= 0.69 and D60= 3/ LL-28%, Pl=19%
Laboratory tests performed on a saturated alluvial subgrade soil gave the following information: In situ water content = 11.9%, Specific gravity = 2.65, Soil size distribution: D100 = 51 mm, D75 = 30 mm, D60 = 20 mm, D45 = 15 mm, D30 = 8 mm, D10 = 4.76 mm, D8 = 2 mm, D4 = 0.08 mm, < 2 m = 4% a. Is this soil well graded? Classify it by the AASHTO and Unified systems b. Using the sieve analysis soil data and the classification systems, estimate for a total of 100% the approximate percentages of coarse aggregate (gravel), fine aggregate (sand), silts, and clays?
Classify the soil using AASHTO. The liquid limit and plastic limit are found to be 30 and 20, respectively. The following data are obtained: Percent passing No. 4 sieve: 100% Percent passing No. 10 sieve: 91% Percent passing No. 40 sieve: 60% Percent passing No. 200 sieve: 20%
Classify the soil by USCS or AASHTO The following data were reported to a soil sample:Percentage of passage of the 4.75 mm sieve = 64Percentage passing Sieve between 75 μ = 6Uniformity Coefficient = 7.5Curvature Coefficient = 2.7Plasticity index = 2.5
Calculate % Silt using the following values; a. Weight of soil= 50 g b. HR reading at 40 sec.= 25 c. Temp at 40 sec= 25 oCd. HR at 2 hrs= 16 e. Temp at 2 hrs= 26 * A. 17.28 B. 17.25 C 17.22 D. 17.19

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Determine the group index of the soil sample no. 6. Sieve analysis (percent finer) Soil Liquid limit Plasticity limit No. No. 4 No. 200 94 3 NP 2 100 77 63 25 3 100 86 55 28 4 100 45 36 22 5 92 48 30 8 6. 60 40 26 4 7 99 76 60 32 Select one O a 5 b. 7 d. none of the choices e.0