Constants | Periodic TablTo determine the molar mass of an unknown gas, itseffusion time was compared to Oscon gas, whichhas a molar mass of 42.005g - mol-1. A sample ofExpress your answer using four significant figures.Oscon was found to effuse from a container in 41.71RateOsconRateunknown= 2.200seconds. The same amount of the unknown gasrequires 91,76 seconds.SubmitPrevious AnswersCompletedPart BRateOsconThe ratio of rates between the two gases, Rate.knownis 2.200. What is the molar mass of the unknown gas?Express your answer using four significant figures.?MMunkg. mol 1

Graham's Law of effusion gives the relationship between the rate of effusion and molar mass of gas…

determine the molar mass of an unknown gas, its usion time was compared to Oscon gas, which sa molar mass of 42.005g - mol-1. A sample of scon was found to effuse from a container in 41.71 Express your answer using four significant figures. RateOscon Ratemknown 2.200 conds. The same amount of the unknown gas quires 91.76 seconds. Submit Previous Answers Completed Part B RateOscon Rateunknown The ratio of rates between the two gases, ,is 2.200. What is the molar mass of the unknown gas? Express your answer using four significant figures. ?

determine the molar mass of an unknown gas, its usion time was compared to Oscon gas, which sa molar mass of 42.005g - mol-1. A sample of scon was found to effuse from a container in 41.71 Express your answer using four significant figures. RateOscon Ratemknown 2.200 conds. The same amount of the unknown gas quires 91.76 seconds. Submit Previous Answers Completed Part B RateOscon Rateunknown The ratio of rates between the two gases, ,is 2.200. What is the molar mass of the unknown gas? Express your answer using four significant figures. ?

Chemistry & Chemical Reactivity

9th Edition

ISBN:9781133949640

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter10: Gases And Their Properties

Section: Chapter Questions

Problem 83GQ: Carbon dioxide, CO2, was shown lo effuse through a porous plate at the rate of 0.033 mol/min. The...

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Starting with the definition of rate of effusion and Graham’s finding relating rate and molar mass, show how to derive the Graham’s law equation, relating the relative rates of effusion for two gases to their molecular masses.
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A gas of unknown identity diffuses at a rate of 83.3 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate of 102 mL/s. Calculate the molecular mass of the unknown gas.
Consider a gas mixture containing equal concentrations of argon and helium. Without performing any calculations, determine which is higher: the number of collisions between helium and helium, the number of collisions between argon and argon, or the number of collisions between helium and argon?
Carbon dioxide, CO2, was shown lo effuse through a porous plate at the rate of 0.033 mol/min. The same quantity of an unknown gas, 0.033 moles, is found to effuse through the same porous barrier in 104 seconds. Calculate the molar mass of the unknown gas.
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93 The complete combustion of octane can be used as a model for the burning of gasoline: 2C8H18+25O216CO2+18H2O Assuming that this equation provides a reasonable model of the actual combustion process, what volume of air at 1.0 atm and 25°C must be taken into an engine to burn 1 gallon of gasoline? (The partial pressure of oxygen in air is 0.21 atm and the density of liquid octane is 0.70 g/mL.)
perform stoichiometric ca1cu1uions for reactions involving gases as reactants or products.