Determine the pH of a buffer formed by dissolving 21.5 g HC-HsO2 and 37.7 g of NaC-H:O2 in 200.0 mL of solution. The value of Ka for HC-H:O2 is 6.3 x 10-5. 2 3 NEXT > Based on the given values, set up ICE table in order to determine the unknown. НС-Н.О-(аq) + H:O(I) H:O“(aq) + C-HsO: (aq) Initial (M) Change (M) Equilibrium (M) 5 RESET 21.5 37.7 0.176 0.261 0.880 1.31 0.178 0.888 -- 21.5 - x 37.7 +x 0.176 - x 0.261 +x 0.880 - x 1.31 + x 0.178 +x 0.888 + x

Principles of Modern Chemistry
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Chapter15: Acid–base Equilibria
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Determine the pH of a buffer formed by dissolving 21.5 g HC-HsO2 and 37.7
g of NaC-H:O2 in 200.0 mL of solution. The value of Ka for HC-H:O2 is 6.3 x
10-5.
1
2
3
NEXT >
Based on the given values, set up ICE table in order to determine the unknown.
HC-HsO:(aq) +
H:O(1)
H;O“(aq)
C-H:O2-(aq)
Initial (M)
Change (M)
Equilibrium (M)
5 RESET
21.5
37.7
0.176
0.261
0.880
1.31
0.178
0.888
21.5 - x
37.7 + x
0.176 - x
0.261 + x
+x
0.880 - x
1.31 + x
0.178 + x
0.888 + x
Transcribed Image Text:Determine the pH of a buffer formed by dissolving 21.5 g HC-HsO2 and 37.7 g of NaC-H:O2 in 200.0 mL of solution. The value of Ka for HC-H:O2 is 6.3 x 10-5. 1 2 3 NEXT > Based on the given values, set up ICE table in order to determine the unknown. HC-HsO:(aq) + H:O(1) H;O“(aq) C-H:O2-(aq) Initial (M) Change (M) Equilibrium (M) 5 RESET 21.5 37.7 0.176 0.261 0.880 1.31 0.178 0.888 21.5 - x 37.7 + x 0.176 - x 0.261 + x +x 0.880 - x 1.31 + x 0.178 + x 0.888 + x
Determine the pH of a buffer formed by dissolving 21.5 g HC-HSO2 and 37.7
g of NaC-H:O2 in 200.0 mL of solution. The value of Ka for HC-H:O2 is 6.3 x
10-5.
PREV
1
2
3
NEXT >
Based on your ICE table and definition of Ka, set up the expression for Ka in order to
determine the unknown. Do not combine or simplify terms.
Ка
= 6.3 x 10-5
=
5 RESET
[0]
[21.5]
[37.7]
[0.176]
[0.261]
[0.880]
[1.31]
[0.178]
[0.888]
[x]
[2x]
[21.5 - x]
[37.7 + x]
[0.176 - x]
[0.261 + x]
[0.880 - x]
[1.31 + x]
[0.178 + x]
[0.888 + x]
Transcribed Image Text:Determine the pH of a buffer formed by dissolving 21.5 g HC-HSO2 and 37.7 g of NaC-H:O2 in 200.0 mL of solution. The value of Ka for HC-H:O2 is 6.3 x 10-5. PREV 1 2 3 NEXT > Based on your ICE table and definition of Ka, set up the expression for Ka in order to determine the unknown. Do not combine or simplify terms. Ка = 6.3 x 10-5 = 5 RESET [0] [21.5] [37.7] [0.176] [0.261] [0.880] [1.31] [0.178] [0.888] [x] [2x] [21.5 - x] [37.7 + x] [0.176 - x] [0.261 + x] [0.880 - x] [1.31 + x] [0.178 + x] [0.888 + x]
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