Determine the rate of reaction for [KI], [HCl], and [KBrO3 from the table with respect to I- (rateI-). Remember that the time you measured was the time for all of the S2O32- to react! Determine the Order with respect to [I-], [HCl], and [KBrO3]
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Determine the
Determine the Order with respect to [I-], [HCl], and [KBrO3]
![Analysis #2
Analysis #3
Exp.
1
2
3
4
Exp.
1
2
3
4
Average Time in seconds used
for rate
9.385
8.315
6.3
4.145
[KI]o / M
0.001
0.002
0.001
0.001
[HCI]o / M
0.015
0.015
0.015
0.03
[KBrO3]0/
M
0.006
0.006
0.012
0.006
rate₁./ (M/s)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc981163a-55a0-47d3-907f-28d0a0a999b8%2Fc0f63efd-0eb2-4dbb-95f0-c6d739364fce%2Fd8j4pha_processed.png&w=3840&q=75)
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- NH4+ {aq) + NO2(aq) -> N2(g) +2H2O{l} Data Initial [NH4+] Initial [NO2-] rate 1 0.0100 0.200 5.4 x10-7 2 0.0200 0.200 10.8x10-7 3 0.0400 0.200 21.5x10-7 4 0.200 0.0202 10.8x10-7 5 0.200 0.0404 21.6x10-7 6 0.200 0.0808 43.3x10-7 Find x,y,kPlease answer fast it’s very important and urgent I say very urgent so please answer super super fast please For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.466Chemistry An aquifer contaminated with petroleum is found to have the following component concentrations at a particular site: benzene158 ppm toluene124 ppm ethylbenzene91 ppm xylene45 ppm n-heptadecane161 ppm pristane 84 ppm Provide an estimate for the age of the spill at this site using (a) BTEX ratio and (b) nC17:Pr ratio. Show your calculations and use units throughout. Give proper s.f. for the answer.
- Show all steps leading to the final answer po. Here’s a pdf file in accordance with the topic po: https://drive.google.com/file/d/1_FnDtXCrFKSol3RNWIG_9tNQ7IxgxD6t/view?usp=drivesdky= mx+ b Slope () = -4E-09 y-intercept () = 0.4021 and OD= 0.540 , Calculate the concentration (x)Benzene is dissolved at a constant initial concentration of 350 mg/l and is contained within a landfill in leachate water above bottom liner of the landfill system. It starts to diffuse through the liner at time t = 0. Using Equation Ci (x,t) = Co erfc x/ 2(D*t)0.5 related narrative, and (error function table), calculate the concentration of benzene at its breakthrough location as it diffuses through a 1.5 meter thick liner (x=1.5 meters represents breakthrough location where liner fails of contaminant is released), after 50 years. Assume D = 10-5 m2/sec (diffusion coefficient in free standing water) and w = 0.7 (coefficient of tortuousity). Clearly present your assumptions and your value of erf, Select the answer range which best fits the answer you calculate. Group of answer choices 315 to 350 mg/l My answer is not in the range of any of the choices my answer. 215 to 314 mg/l 175 to 200 mg/l 370 to 400 mg/l
- A fly ash aerosol of monodisperse particles with a density of 2.0 g/mL and particle diameter of 10.0 mm has a concentration of 1000.0 mg/m3. Calculate the settling velocity in cm/s and the settling rate in g/m2-s. Please answer very soon will give rating surelyPlease answer super fast and answer all questions and show calculations For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.4660% 25% 50% 75% 100% Depth of H2O2 Solution (d) 2.1 cm 2.1 cm 2.1 cm 2.1 cm 2.1 cm Trial 1 Time 180 sec 84.61 sec 43.52 sec 36.90sec 25.90 sec Trial 2 Time 180 sec 92.25 sec 38.16 sec 34.36 sec 23.57sec Trial 3 Time 32.53 sec 18.82 sec Average Time (t) 180 sec 88.43 sec 40.84 Sec 34.5 sec 22.76 sec Rate of the Reaction(R = d/t) 0.012 cm/sec 0.02 cm/sec 0.051 cm/sec 0.061 cm/sec 0.0923cm/sec , graph rate of reaction on the y-axis and percent concentration of enzyme on the x-axis. If the points are linear, draw a “best-fit” straight line through or near all of the data points. Based on the information in the data table and your graph, explain the relationship between percent concentration of catalase and rate of reaction. Did your actual results match your hypotheses? If not, why?
- There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…Amylum, commonly known as starch is a white powder with variable molecular formula due to the different number of repeating sugar units based on the plant that it is obtained from. A sample of amylum in the form of spherical beads was subjected to series of analyses to determine physicochemical properties in the quality control unit of a factory. From the results each bead is found to have a 4.5 mL volume and 1.47 g/mL density. 4 of the beads were placed in a reaction chamber combusted, as a result, 43.1 g CO2 and 14.7 g H2O were obtained. If the molecular weight of the amylum is 972.84 g/mol how many repeating units the starch molecule consist and what is the molecular formula of the starch? [Empirical Formula=CxHyOz, Repeating unit=n, Molecular Formula=( CxHyOz)*n= CnxHnyOnz]