Determine the type of inhibition by AMP? Explain
Biomedical Instrumentation Systems
1st Edition
ISBN:9781133478294
Author:Chatterjee
Publisher:Chatterjee
Chapter3: Biosignals And Noise
Section: Chapter Questions
Problem 8P
Related questions
Question
Determine the type of inhibition by AMP? Explain
![[AMP]=0
[AMP]=1 mM [AMP]=2 mM [AMP]=3 mM [AMP]=4 mM [AMP]=5 mM
[CH;CHO]
Vo
Vo
Vo
Vo
Vo
Vo
1.00
0.096
0.049
0.033
0.024
0.020
0.016
1.50
0.128
0.065
0.043
0.033
0.026
0.022
2.50
0.175
0.089
0.059
0.045
0.036
0.030
5.00
0.238
0.122
0.082
0.061
0.049
0.041
50
y = 47.5837x + 14.4554
R? = 0.9989
[AMP] = 5 mM
y = 37.2228x + 13.0690
R? = 0.9991
[AMP] = 5 mM
[AMP] = 4 mM
40
y = 31.5867x + 9.7472
R? = 0.9986
[AMP] = 3 mM
[AMP] = 4 mM
y = 22.6680x + 7.8306
R? = 0.9991
[AMP] = 2 mM
30
[AMP] = 3 mM
y = 15.2885x + 5.1429
[AMP] = 1 mM
R? = 1.0000
20
[AMP] = 2 mM
y = 7.7837x + 2.6255
R? = 1.0000
[AMP] = 0 mM
[AMP] = 1 mM
10
(AMP] = 0 mM
-0.500
-0.300
-0.100
0.100
0.300
0.500
0.700
1/[S]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F559d488a-a712-4921-ad37-ac371a2b1b6a%2F350086dc-cd0f-4745-b239-9ba72a62106c%2Fq3zyw0f_processed.png&w=3840&q=75)
Transcribed Image Text:[AMP]=0
[AMP]=1 mM [AMP]=2 mM [AMP]=3 mM [AMP]=4 mM [AMP]=5 mM
[CH;CHO]
Vo
Vo
Vo
Vo
Vo
Vo
1.00
0.096
0.049
0.033
0.024
0.020
0.016
1.50
0.128
0.065
0.043
0.033
0.026
0.022
2.50
0.175
0.089
0.059
0.045
0.036
0.030
5.00
0.238
0.122
0.082
0.061
0.049
0.041
50
y = 47.5837x + 14.4554
R? = 0.9989
[AMP] = 5 mM
y = 37.2228x + 13.0690
R? = 0.9991
[AMP] = 5 mM
[AMP] = 4 mM
40
y = 31.5867x + 9.7472
R? = 0.9986
[AMP] = 3 mM
[AMP] = 4 mM
y = 22.6680x + 7.8306
R? = 0.9991
[AMP] = 2 mM
30
[AMP] = 3 mM
y = 15.2885x + 5.1429
[AMP] = 1 mM
R? = 1.0000
20
[AMP] = 2 mM
y = 7.7837x + 2.6255
R? = 1.0000
[AMP] = 0 mM
[AMP] = 1 mM
10
(AMP] = 0 mM
-0.500
-0.300
-0.100
0.100
0.300
0.500
0.700
1/[S]
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