Determine the weld leg size needed to fully develop the strength of the plate shown using A-36 steel and E60 electrodes. Use LRFD. 120 PL150X8 L- 100
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- Find the size of E70 fillet weld required for the shear and tension connection shown. Use the following details: P = 250 kNe = 130 mmb = 150 mmd = 200 mmAssume the column and bracket plate does not control the strength.Design a weld connection for an UNP 280×80×9 of S 355 (fy= 355 MPa and fu= 470MPa) steel connected to a 10 mm gusset plate. The guesst plate is S275. Please draw all calculated values on a sketch with full dimensions.Design a weld connection for an UNP 280×80×9 of S 355 (fy= 355 MPa and fu= 470MPa) steel connected to a 10 mm gusset plate. The guesst plate is S275. Please draw all calculated values on a sketch with full dimensions. D= 335 KNL= 670 KN
- What size of fillet welds are required to attach a 16 mm flat plate hanger to the bottom flange of a UB 457 x 152 x 74 so that the full tensile capacity of the hanger may be developed ? Calculate the effective width (beff) of the weld. Assume the use of S355 steel for UB and the plate and the width of the plate is the same as the flange width of UB .Select an American Standard Channel shape for the following tensile loads: dead load = 54 kips, live load = 80 kips, and wind load = 75 kips. The connection will be with longitudinal welds. Use an estimated shear lag factor of U = 0.85. (In a practical design, once the member was selected and the connection designed, the value of U would be computed and the member design could be revised if necessary.) The length is 17.5 ft. Use Fy=50 ksi and Fu=65 ksi. a. Use LRFD. b. Use ASD.a. Use LRFD and design a welded connection for the bracket shown in Figure P8.4-19. All structural steel is A36. The horizontal 10-inch dimension is a maximum. b. State why you think your weld size and configuration are best.
- Use an elastic analysis and compute the extra load in the weld (in kips per inch of length) caused by the eccentricity.Use an elastic analysis and determine the maximum load per inch of weld.A WT6x15 shape made from A36 steel will be welded along its flanges to a gusset plate. Determine the LRFD available strength, φRn, for gross tension yield of the WT shape. Determine the required weld length, l, on each side of the WT in order to exceed the LRFD available strength for gross tension yield of the WT shape. Assume a weld size of w=5/16 inch and E70XX electrodes. Based on the weld length, compute the available LRFD strength, φRn, for tensile rupture of the WT shape.
- Determine the total LFRD design strength and the total ASD allowable strength of the 5/16 – in E70 fillet welds shown.A 4 x 4 x ½ - in. angle of A36 steel is to be welded to a plate with E70XX electrodes to develop the full tensile strength of the angle. Using 3/8-in. fillet welds, compute the design lengths for the welds on the two sides of angle, assuming development of tension on the full cross section of the angles. GIVEN: A = 3.75 in2 L1 = 10.94” L2 = 5.09” IF only connected leg, L = 7.7”; 4.75 each sideGiven: use A36 steel and an estimated shear lag factor. U of 0.85 Required: select an angle-shape for the tension member of the loaded truss as shown. All connections are with longitudinal welds.