Develop the analysis of variance computations for the following completely randomized design. At a= 05, is there a significant difference between the treatment means? Treatment 143 117 113 116 109 124 117 102 79 94 105 90 113 110 114 91 103 100.10 128.99 132 122 122 99 104 103 101 106 94 93 106.20 92.18 , 120.50 * 170.57 Use the , from the table to compute (to 2 decimals) Source of Sum of Degrees Mean Square of Freedom F (to 2 Pvalue (to 4 Variation Squares (to 2 decimals) decimals) (to 2 decimais) decimals) Treatments Error Total

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter8: Sequences, Series, And Probability
Section8.7: Probability
Problem 58E: What is meant by the sample space of an experiment?
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Develop the analysis of varlance computations for the following completely randomized design. At a = .05, is there a significant difference between the
treatment means?
Treatment
B
143
117
113
116
132
122
122
99
109
124
117
111
104
103
101
106
94
93
106.20
92.18
102
79
94
105
90
113
110
114
91
103
100.10
128.99
, 120.50
* 170.57
Use the , from the table to compute (to 2 decimals)
Source of
Sum of
Degrees Mean Square
of Freedom
F (to 2
decimals)
pvalue (to 4
Variation
Squares
(to 2
decimals)
(to 2 decimals)
decimals)
Treatments
Error
Total
The p-value is lese than 0.01
What is your conclusion7
Conclude nat all treatment means are equal
Transcribed Image Text:Develop the analysis of varlance computations for the following completely randomized design. At a = .05, is there a significant difference between the treatment means? Treatment B 143 117 113 116 132 122 122 99 109 124 117 111 104 103 101 106 94 93 106.20 92.18 102 79 94 105 90 113 110 114 91 103 100.10 128.99 , 120.50 * 170.57 Use the , from the table to compute (to 2 decimals) Source of Sum of Degrees Mean Square of Freedom F (to 2 decimals) pvalue (to 4 Variation Squares (to 2 decimals) (to 2 decimals) decimals) Treatments Error Total The p-value is lese than 0.01 What is your conclusion7 Conclude nat all treatment means are equal
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