Deviation( ) Deviation( ) Height( ) x-mean| Diameter( ) |x-mean| 0.06568 0.06568 0.06553 0.06566 0.122 0.12230 1 65.68 2 2 65.98 3 0.12230 3 65.53 0.12155 65.66 Mean( )=0.12214 Mean( )= 月 % error=0.06% 65.71 Mean-0.06564 % error=0.41 % • Think about potential errors by observing the pictures for example, were all diameters measured at the same place for coin, soda-like can etc. and decide whether the resulting error is random or systematic. • Record your results in meters, if you want to simplify your volume calculations. Then calculate the volume of a right circular eylinder, using: nd²h V = m?h = 4 where d is the mean diameter and h is the mean height. Error Analysis Note that to calculate the percent error in volume, you must add twice the percent error in the diameter to the percent error in height, that is: % error in V = 2 x % error in diameter + % error in height To find the standard deviation associated with the volume you must multiply the percent error in the volume times the mean value of the volume and divide the result by 100, that is, %errorx X 100 Also, it is best to use scientific notation to express your results in the form: V = 4.01±0.05x104 m³ (1%). Volume of Cylinder= % Error= Oy=

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with given data I need help to find the standard deviation on both charts, and finding the volume of cyilender with the error % and standard deviation at the bottom of page, thank you!

Deviation( )
Deviation( )
Height( )
|Xr-mean|
Diameter( )
|x-mean|
0.06568
0.06568
0.122
65.68
0.12230
0.12230
0.12155
2
65.98
0.06553
0.06566
3
3
65.53
65.66
Mean( )= 0.12214
Mean( )=
o )=
% error= 0.06%
65.71
Mean-0.06564
% error= 0.41 %
Think about potential errors by observing the pictures for example, were all diameters
measured at the same place for coin, soda-like can etc. and decide whether the resulting error is
random or systematic.
• Record your results in meters, if you want to simplify your volume calculations.
Then calculate the volume of a right eireular eylinder, using:
nd?h
V = m?h:
4
where d is the mean diameter and h is the mean height.
Error Analysis
Note that to calculate the percent error in volume, you must add twice the percent error in
the diameter to the percent error in height, that is:
% error in V = 2 x % error in diameter + % error in height
To find the standard deviation associated with the volume you must multiply the percent error
in the volume times the mean value of the volume and divide the result by 100, that is,
%errorx I
100
Also, it is best to use scientific notation to express your results in the form:
V = 4.01+0.05x10-4 m³ (1%).
Volume of Cylinder=
% Error=
Ov=
2.
Transcribed Image Text:Deviation( ) Deviation( ) Height( ) |Xr-mean| Diameter( ) |x-mean| 0.06568 0.06568 0.122 65.68 0.12230 0.12230 0.12155 2 65.98 0.06553 0.06566 3 3 65.53 65.66 Mean( )= 0.12214 Mean( )= o )= % error= 0.06% 65.71 Mean-0.06564 % error= 0.41 % Think about potential errors by observing the pictures for example, were all diameters measured at the same place for coin, soda-like can etc. and decide whether the resulting error is random or systematic. • Record your results in meters, if you want to simplify your volume calculations. Then calculate the volume of a right eireular eylinder, using: nd?h V = m?h: 4 where d is the mean diameter and h is the mean height. Error Analysis Note that to calculate the percent error in volume, you must add twice the percent error in the diameter to the percent error in height, that is: % error in V = 2 x % error in diameter + % error in height To find the standard deviation associated with the volume you must multiply the percent error in the volume times the mean value of the volume and divide the result by 100, that is, %errorx I 100 Also, it is best to use scientific notation to express your results in the form: V = 4.01+0.05x10-4 m³ (1%). Volume of Cylinder= % Error= Ov= 2.
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