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A: question 31 Ethyl amine is most basic due to +I effect of alkyl on nitrogen lone pair.
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A: Given molecule is ketone.
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A: We will use Boyle's law to get final pressure.
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- Determine the average rate of change of BB from ?=0 st=0 s to ?=272 s.t=272 s. A⟶2BA⟶2B Time (s) Concentration of A (M) 0 0.7300.730 136136 0.4450.445 272272 0.1600.160 rateB= __________M/sThe kinetics of the austenite-to-pearlite transformation obey the Avrami equation and that the value of n in the exponential is 2.5. If, at some temperature, the fraction transformed-time data given here, determine the total time required for 95% of austenite to transform to pearlite:hello, i sent this question before but the answer you rpovided for both wasnt right and i couldnt undertstand how you got the answer. can you please show me a handwritten solution for better understanding. 1a) The decomposition of ethanol at some constant temperature (above 500°C), over a copper surface, C2H5OH(g) CH3CHO(g) + H2(g) was studied by monitoring the total pressure with time.The following data were obtained: t (s) Ptotal (torr) 0 120 45 131 139 154 233 177 376 212 380 213 What will be the total pressure at t = 462 s? 1b) What is the rate constant (k)?(Include appropriate units.)
- DEQ: A fungal specie of cordyceps turns humanity into a zombie-like state. The rate of growth of a singlecordyceps was observed and was determined to be proportional to itself. If between noon and 2:00PM, the population triples, at what time, no controls being exerted, should the cordyceps becomes 100times what it was in noon?Sodium chlorate crystals are easy to grow in the shape of cubes by allowing a solution of water and sodium chlorate to evaporate slowly. a. If V is the volume of such a cube with side length x, calculate dV/dx when x = 3 mm and explain its meaning (be specific). b. Show that the rate of change of the volume of a cube with respect to its edge length is equal to half the surface area of the cube.Calculate the avergae rate of disappearance for N2O5 between 200 seconds and 500 seconds, if the concentration was determined to be 0.0165 M at 200 seconds and 0.0047 at 500 seconds at a constant 300°C.
- The oxidation of HSO3− by O2 in an aqueous solution is a reaction of importance to the processes of acid rain formation and flue gas desulfurization. R.E. Connick et al. (Inorg. Chem. 34, 4543 (1995)) report that the reaction 2 HSO3−(aq) + O2(g) → 2 SO42−(aq) + 2 H+(aq) follows the rate law v = kr[HSO3−]2[O2]2. Given pH = 5.6 and an O2 molar concentration of 0.24 mmol dm−3 (both presumed constant), an initial HSO3− molar concentration of 50 μmol dm−3, and a rate constant of 3.6 × 106 dm9 mol−3 s−1, what is the initial rate of reaction? How long would it take for HSO3− to reach half its initial concentration?Consider a polymer formed by a chain process. By how much does the kinetic chain length change if the concentration of initiator is increased by a factor of 3.6 and the concentration of monomer is decreased by a factor of 4.2?a. Express the rate in terms of change of concentration of A with respect to time where 2A + B -> products, rate = k[A]-1. b. Give the derived integrated rate law. c. What is the derived expression for half-life with respect to A in terms of k and [A]o?
- The decomposition of aqueous sucrose to form the isomers glucose and fructose is a common organic reaction, which requires a strong catalyst: C12H22O11(aq) + H2O(l) → 2C6H12O6(aq). The following data were collected during the process: Time (min) [C12H22O11] (mol/L) 0 0.316 39 0.274 80 0.238 140 0.190 210 0.146 Use the following grids to plot three separate graphs of [C12H22O11], ln[C12H22O11], and 1/[C12H22O11] against time to determine the reaction order. (a)Write the rate law expression in its general form (water should not be included). (b)Determine the rate constant with units. (c)Determine the half-life. (d)If we performed a new trial with an initial concentration of sucrose of 0.400 mol/L, what concentration would remain after 4.0 h has passed?Rates of diffusion are often given in moles per second. Rates of diffusion usually vary with distance and we can examine the diffusion across a square meter. Assuming we study the diffusion of carbon dioxide across this square meter at different temperatures but otherwise identical conditions, what is the predicted rate of diffusion of carbon dioxide at 78°C if the rate of diffusion at 32°C across this square meter is 5.2 × 10–9 moles/sec?From the equation of the line of best fit for the temperature-rate constant data in Part C, y= -22314x + 25.181 determine the value of Ea in kJ/mol. Include a unit analysis. R is a constant equal to 8.314 J/molK. When you take the natural log of a number, the units disappear.