3.Weight 80 344 416 348Age 19 55 81 115262 360 332 3456 51 68 8Enter the values for Weight in column 1 and the values for Age in column 2. SelectAnalysis, then Correlation and Regression.a) Find the equation of the regression line.b) What is the best predicted age of a bear that weighs 300 lb? (Use your calculator)4. Use a 0.01 significance level to test the claim that the mean cotinine level is thesame for the following three groups:1) People who smoke (Smokers).2) Nonsmokers who are exposed to "second-hand" smoke at home or work (ETS).3) Nonsmokers not exposed to environmental tobacco smoke at home or work(NOETS).Click on Datasets, then Elementary Stats 11th Edition, then Passive and ActiveSmoke. Select Analysis from the main menu, and then select One-Way Analysis ofVariance. Check # 1, 2, 3, and then click Evaluate.a) Critical Fb) Test Statistic F:b) Initial Conclusiond) Final Conclusion Math V44 - Computer 3NameDO NOT ROUND YOUR ANSWERS!! SHOW ALL DECIMAL PLACES!!1. Select Analysis, then Hypothesis Testing. Choose Proportion One Sample.Test the claim that the population proportion of successes equals 0.5. There were100 observations and 61 of them were successes. Repeat the test for eachsignificance level.Significance Level0.050.01Critical ValuesTest StatisticInitial Conclusion (Ho)When the significance level is changed to a smaller value, thebecomes larger or smaller (choose one) in absolute value.2. An instructor gives a test before and after a lesson. The results are:Before 4247533761884550After 7275807090988183Bring back the Sample Editor. Enter the Before values in column 1 and the Aftervalues in column 2. Select Analysis, then Hypothesis Testing, then Mean-Matched Pairs. At the 0.05 significance level, test the claim that the lesson hasno effect on the test scores.a) Critical Valuesb) Test Statisticc) Initial Conclusiond) Final Conclusion

Question

3.Weight 80 344 416 348Age 19 55 81 115262 360 332 3456 51 68 8Enter the values for Weight in column 1 and the values for Age in column 2. SelectAnalysis, then Correlation and Regression.a) Find the equation of the regression line.b) What is the best predicted age of a bear that weighs 300 lb? (Use your calculator)4. Use a 0.01 significance level to test the claim that the mean cotinine level is thesame for the following three groups:1) People who smoke (Smokers).2) Nonsmokers who are exposed to &#34;second-hand&#34; smoke at home or work (ETS).3) Nonsmokers not exposed to environmental tobacco smoke at home or work(NOETS).Click on Datasets, then Elementary Stats 11th Edition, then Passive and ActiveSmoke. Select Analysis from the main menu, and then select One-Way Analysis ofVariance. Check # 1, 2, 3, and then click Evaluate.a) Critical Fb) Test Statistic F:b) Initial Conclusiond) Final Conclusion Math V44 - Computer 3NameDO NOT ROUND YOUR ANSWERS!! SHOW ALL DECIMAL PLACES!!1. Select Analysis, then Hypothesis Testing. Choose Proportion One Sample.Test the claim that the population proportion of successes equals 0.5. There were100 observations and 61 of them were successes. Repeat the test for eachsignificance level.Significance Level0.050.01Critical ValuesTest StatisticInitial Conclusion (Ho)When the significance level is changed to a smaller value, thebecomes larger or smaller (choose one) in absolute value.2. An instructor gives a test before and after a lesson. The results are:Before 4247533761884550After 7275807090988183Bring back the Sample Editor. Enter the Before values in column 1 and the Aftervalues in column 2. Select Analysis, then Hypothesis Testing, then Mean-Matched Pairs. At the 0.05 significance level, test the claim that the lesson hasno effect on the test scores.a) Critical Valuesb) Test Statisticc) Initial Conclusiond) Final Conclusion

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Question 1
Given that…