Do not use static variables to implement recursive methods. USING JAVA Indicate the order of the following growth functions using < (e.g. n < n2) n2 log n n n2/ log n n! (1.5)n 3n
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Do not use static variables to implement recursive methods.
USING JAVA
Indicate the order of the following growth functions using < (e.g. n < n2)
- n2 log n
- n
- n2/ log n
- n!
- (1.5)n
- 3n
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- Which is the base case of the following recursion function: def mult3(n): if n == 1: return 3 else: return mult3(n-1) + 3 else n == 1 mult3(n) return mult3(n-1) + 3Do not use static variables to implement recursive methods. USING JAVA USING: // P4 public static int min(int [] a, int begin, int end) { } Implement a recursive method min that accepts an array and returns the minimum element in the array. The recursive step should divide the array into two halves and find the minimum in each half. Demonstrate the output of min on the array int [] a = { 2, 3, 5, 7, 11, 13, 17, 19, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 23, 29, 31, 37, 41, 43 }What type of recursion is used in the following function? int f(int n){ if (n==1) return 1; else return n+f(n-1); } Tail recursion Multiple recursion Indirect recursion Non-tail recursion
- is it correct ? Write a recursive function that returns the nth number in a fibonacci sequence when n is passed to function. The fibonacci sequence is like 0,1,1,2,3,5,8,13...... Answer: #include <iostream> using namespace std; int getFibonacci(int n) { if (n == 0 || n == 1) return n; else return getFibonacci(n - 1) + getFibonacci(n - 2); } int main() { int n = 7; int result = getFibonacci(n); cout << result; }Write a recursive function that, given a sequence of comparable values, returns the count of elements where the current element is less than the following ( next ) element in the given sequence. See the examples given below. def count_ordered ( seq ) : """ Input : A sequence of comparable elements Output : The number of elements that are less than the following element in the sequence Example : >>> count_ordered ( [ 1 , 2 , 3 , 4 , 5 , 6 ] ) 5 >>> count_ordered ( ( 1 , 12, 7.3 , -2,4 ) ) 2 >>> count_ordered ( 'Python' ) 2 >>> count_ordered ( [ 6 ] ) 0 >>> count_ordered ( [ ] ) 0 """ In the first example above , count_ordered ( [ 1,2,3,4,5,6 ] )the returned answer is 5 because for all the first 5 numbers the current number is less than the next number. In the second example above, count_ordered ( ( 1,12,7.3 , -2,4 ) )the…This is for Java Write a recursive function that takes as a parameter a nonnegative integerand generates the following pattern of stars. If the nonnegative integer is 4,then the pattern generated is:**********Also, write a program that prompts the user to enter the number of lines inthe pattern and uses the recursive function to generate the pattern. Forexample, specifying 4 as the number of lines generates the above pattern. Java please
- Java, I am not displaying my results correct. It should add up the digits in the string. input string |result for the sumIt Recursion functions and a findMax function that finds the largest number in a string "1d2d3d" | 6 total "55" |10 total "xx" | 0 total "12x8" |12 Max number "012x88" |88 Max Number "012x88ttttt9xe33ppp100" |100 Max Number public class Finder { //Write two recursive functions, both of which will parse any length string that consists of digits and numbers. Both functions //should be…The first examples of recursion are the mathematical functions factorial and fibonacci. These functions are defined for non-negative integers using the following recursive formulas:factorial(0) = 1factorial(N) = N*factorial(N-1) for N > 0fibonacci(0) = 1fibonacci(1) = 1fibonacci(N) = fibonacci(N-1) + fibonacci(N-2) for N > 1Write recursive functions to compute factorial(N) and fibonacci(N) for a given non-negative integer N, and write a main() routine to test your functions.(In fact, factorial and fibonacci are really not very good examples of recursion, since the most natural way to compute them is to use simple for loops. Furthermore, fibonacci is a particularly bad example, since the natural recursive approach to computing this function is extremely inefficient.)Use the recursion to solve the following problems 1. Calculate the sum of an array of n integers. 2. Compute Powers, p(x,n)=xn 3. Revers an array of n integers 4. Calculate the length of string (number of characters) 5. Implement the tail recursion for problems 1 and 2. Please test the program by using 2 different input sets!
- Please answer fast Question 1 Answer following questions and write corresponding algorithms. Algorithm: sqrt(n) [main] 1. return sqrtHelper(Arg 1, Arg 2) Algorithm: sqrtHelper(n,m) 1. if m*m <= n 2. return m 3. else 4. return sqrtHelper(Arg 3, Arg 4) 5. endif (a) Write an recursive algorithm called isPrime(n) that takes a positive integer and returns True if it is prime and False otherwise. You must call the function sqrt(n) as a sub- algorithm. Trace your algorithm for isPrime(41). You only need to show the detail in the main algorithm and its helper function (if there is any).JAVA Question 2: For two integers m and n, their GCD (Greatest Common Divisor) can be computed by a recursive method. Write a recursive method gcd(m,n) to find their Greatest Common Divisor. Method body: If m is 0, the method returns n. If n is 0, the method returns m. If neither is 0, the method can recursively calculate the Greatest Common Divisor with two smaller parameters: One is n, the second one is m mod n (or m % n). The recursive method cannot have loops. Note: although there are other approaches to calculate Greatest Common Divisor, please follow the instructions in this question, otherwise you will not get the credit. main method: Prompt and read in two numbers to find the greatest common divisor. Call the gcd method with the two numbers as its argument. Print the result to the monitor. Example program run: Enter m: 12 Enter n: 28 GCD(12,28) = 4 And here is what I have so far, package CSCI1302;import java.util.*;public class RecursionDemo { public static void…T/F 6. Consider the following recursive sum method:public int sum(int x){if (x == 0) return 0;else return sum(x - 1) + 1;}