need help with: D,E,F , G, Hplease thank you ! Do rats take more time on average than hamsters to travel through a maze? The table below shows the times inseconds that the rats and hamsters took.Rats: 12, 30, 34,42, 28,20, 47, 33, 24, 53Hamsters: 33, 29,23,15, 19,20,42,25Assume that both populations follow a normal distribution. What can be concluded at the a = 0.01 level ofsignificance level of significance?For this study, we should useSelect an answera. The null and alternative hypotheses would be:Но:Select an answerSelect an answer(please enter a decimal)?H1:Select an answer(Please enter a decimal)?Select an answerb. The test statistic ?(please show your answer to 3 decimal places.)c. The p-value =d. The p-value is ?(Please show your answer to 4 decimal places.)e. Based on this, we should Select an answerO the null hypothesis.f. Thus, the final conclusion is thatOThe results are statistically significant at a = 0.01, so there is sufficient evidence to conclude thatthe population mean time to complete the maze for rats is more than the population mean time tocomplete the maze for hamsters.OThe results are statistically insignificant at a = 0.01, so there is statistically significant evidence toconclude that the population mean time to complete the maze for rats is equal to the populationmean time to complete the maze for hamsters.OThe results are statistically insignificant at a = 0.01, so there is insufficient evidence to concludethat the population mean time to complete the maze for rats is more than the population mean timeto complete the maze for hamsters. to complete the maze for hamsters.OThe results are statistically significant at a = 0.01, so there is sufficient evidence to conclude thatthe mean time to complete the maze for the ten rats is more than the mean time to complete themaze for the eight hamsters.g. Interpret the p-value in the context of the study.OThere is a 10.44% chance of a Type I error.Olf the sample mean time to complete the maze for the 10 rats is the same as the sample mean time tocomplete the maze for the 8 hamsters and if another 10 rats and 8 hamsters are observed then therewould be a 10.44% chance of concluding that the mean time to complete the maze for the 10 rats isat least 6.6 seconds longer than the mean time to complete the maze for the 8 hamsters.If the population mean time to complete the maze for rats is the same as the population mean time tocomplete the maze for hamsters and if another 10 rats and 8 hamsters are observed then there wouldbe a 10.44% chance that the mean time to complete the maze for the 10 rats would be at least 6.6seconds longer than the mean time to complete the maze for the 8 hamsters.There is a 10.44% chance that the mean time to complete the maze for the 10 rats is at least 6.6seconds longer than the mean time to complete the maze for the 8 hamsters.h. Interpret the level of significance in the context of the study.OThere is a 1% chance that the population mean time to complete the maze for rats and hamsters isthe same.OIf the population mean time to complete the maze for rats is the same as the population mean time tocomplete the maze for hamsters and if another 10 rats and 8 hamsters are observed then there wouldbe a 1% chance that we would end up falsely concluding that the population mean time to completethe maze for rats is more than the population mean time to complete the maze for hamstersOThere is a 1% chance that the rat will eat the hamster.OIf the population mean time to complete the maze for rats is the same as the population mean time tocomplete the maze for hamsters and if another 10 rats and 8 hamsters are observed, then therewould be a 1% chance that we would end up falsely concluding that the sample mean time tocomplete the maze for these 10 rats and 8 hamsters differ from each other.

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Difference Scores CalculationsTreatment 1N1: 10df1 = N - 1 = 10 - 1 = 9M1: 32.3SS1: 1398.1s21 =…