ChemistryHow would you prepare 100.00 mL of 0.100 M phosphate buffer at pH 7.00 using solid KH,PO, and K2HPO,?MM KH;PO4: 136.08MM KHPO: 174.2Ka = 6.2 x 108H,PO,HPO,2- + H*RUSH. Please show the solution. Step bystep. Thank you. Will upvote after.

Given: pH of buffer = 7.00 Concentration of solute in buffer = 0.100 M Volume of buffer solution =…

Answered: How would you prepare 100.00 ml of…

How would you prepare 100.00 ml of 0.100 M phosphate buffer at pH 7.00 using solid KH,PO, and K2HPO4? MM KH,PO4: 136.08 MM K,HPO: 174.2 Ka - 6.2 x 10 H2PO, = HPO,2- + H*

Appl Of Ms Excel In Analytical Chemistry

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ISBN:9781285686691

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Chapter8: Polyfunctional Acids And Bases

Section: Chapter Questions

Problem 10P

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

Chemistry
How would you prepare 100.00 mL of 0.100 M phosphate buffer at pH 7.00 using solid KH,PO, and K2HPO,?
MM KH;PO4: 136.08
MM KHPO: 174.2
Ka = 6.2 x 108
H,PO,
HPO,2- + H*
RUSH. Please show the solution. Step by
step. Thank you. Will upvote after.

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Follow-up Question

Assuming that the buffer has y concentration of KH2PO4.

Hence the concentration of K2HPO4 in buffer = 0.100 - y

Does the 0.100 came from the conversion of 100 mL? Or is it from the given 0.100 M buffer?

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Please show how you got 0.06173.

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