Draw the structure of the compound whose data is shown below. Upload your answer to receive fullcredit.C9H,NO3There are 7 C-NMR signals. The compound is significantly deactivated toward electrophilic aromaticsubstitution.H-NMR:12.7 ppm, s, 1H10.3 ppm, s 1H7.91 ppm, d, 2H7.72 ppm, d, 2H2.10 ppm, s 3H

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Answered: Draw the structure of the compound…

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter24: Carboxylic Acids & Derivatives

Section: Chapter Questions

Problem 2E

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please help with this question. thank you. Given that compound X has a molecular formula of C6H10O2, gave three peaks in its 13C NMR spectrum (14, 63 and 158 ppm) and two peaks in its 1H NMR spectrum (1.4 ppm, triplet and 4.3 ppm, quartet), provide a structure for compound X and briefly explain.
Please show complete answer. Propose a structure consistent with following set of spectral data: a. C5H10O2: IR peak at 1740 cm−1; NMR (ppm): 1.15 (triplet, 3 H) 2.30 (quartet, 2 H) 1.25 (triplet, 3 H) 4.72 (quartet, 2 H) b. C3H6O: IR peak at 1730 cm−1; NMR (ppm): 1.11 (triplet) 2.46 (multiplet) 9.79 (triplet)
ORGANIC CHEMISTRY PLEASE EXPLAIN, SEE PHOTO: A compound, with molecular formula C5H10Br2 displays the following 13C NMR along with the DEPT-90 and DEPT-135 13C NMR spectra. Identify the structure of this compound. Please annotate each of the spectra, explaining what each signal or absence of signal means and the information obtained from each.
16 Draw the structures of Compound 16a and 16b, clearly indicate your assignments of all proton resonances. Calculate the unsaturation index of each compound Compound 16a- c8h6o2 A=10.2 ppm singlet 2h B=7.69 ppm singlet 4h Compound 16b C8H10 A=7.00 ppm, singlet 4h B= 2.25 ppm singlet 6H (Excess) H2NNH2, KOH, (HOCH2CH2)2O heat
Draw the structure that gives the NMR below. The compound has the molecular formula, C5H10O2. Signal at 3.61(singlet, 3H), 2.32(triplet, 2H), 1.68(sextet, 2H) and 0.99(triplet, 3H). IR shows strong bands at 1710 cm-1and 1200 cm-1(in addition to others). **Make sure to indicate (label) which hydrogen gives which signal.
Draw the structure that gives the NMR below. The compound has the molecular formula, C5H10O2.Signal at 4.13 (triplet, 2H), 2.04 (singlet, 3H), 1.73 (sextet, 2H) and 1.01 (triplet, 3H). IR shows strong bands at 1710 cm-1and 1200 cm-1(in addition to others). *Make sure to indicate (label) which hydrogen gives which signal.
answer with detail explanation , explain H1 nmr , IR , 13C ,DEPT
An unknown compound has the molecular formula C7H14O, and its 1H NMR and 13C NMR spectra are shown below. Determine the structure of the unknown compound and draw it below. Note that there are no peaks above 3 ppm in the 1H NMR, and the numbers present on the 1H NMR are the integration values for each set of peaks.
Draw the structures of Compound 13 a and 13b, clearly indicate your assignments of all proton resonances. Calculate the unsaturation index of each compound Compound 13a: C8H10O2 A=7.17 ppm singlet 4h B=4.70 ppm singlet 4h C= 2.99 ppm singlet 2H 1)Excess CrO3, H2SO4 2) CH3OH (excess) , H+ heat Compound: C10H10O4 A=8.11 ppm singlet 4H B=3.96 ppm singlet 6 H
Predict which proton will have the most downfield and upfield signal in the ¹H NMR spectrum.
I have an NMR spectrum. There are 5 peaks. There is a doublet at 9.6 ppm (integrates to 2H) where aldehydes usually arise, don't know why there is a doublet. There is another doublet at 6.8 ppm, again integrating to 2H. There is a singlet at 4.5 ppm, integrating to 1H. There is a quartet at 3.4 ppm integrating to 2H, and lastly there is triplet at 1.2 ppm integrating to 3H. i recofnize the ethyl group but don't understand the peak at 9.6 unless it is not an aldehyde.
Propose a structure consistent with each set of data.

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