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- 1) What is the major product for the reaction of 3-bromo1-butene and HBr? Give the name of the product. 2) For this product, how many chiral carbon(s) are there in the structure?3) How many stereoisomers could we write for this product? 4) Write the Fischer Projections of all stereoisomers. (attach a file or other ways you could show your work)Which statement best describes the product mixture after (R)-3-chloro-3-methylhexane undergoes an SN1 reaction? a. The product mixture would be 100% R enantiomer b. The product mixture would be 100% S enantiomer c. The product mixture would be racemic d.The product mixture would be 100% cis isomer e.The product mixture would be 100% trans isomerMonensin (1) is a potent antibiotic. JACS 1980, 102, 2118-2120. 1. Use arrows provided a pathway from (1) to (2) when we add a mild base sodium bicarbonate followed by iodine (I2). 2. What was a similar reaction between Br2 and an alkene? What did we name the intermediate?
- Draw the structure(s) of the major organic product(s) obtained after workup of the following reaction. Use the wedge/hash bond tools to indicate stereochemistry where it exists. If no reaction occurs, draw the organic starting material. Draw structure(s) of product(s) after aqueous workup. Include counter-ions, e.g., Na+, I-, in your submission, but draw them in their own separate sketcher. Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner.C6H5CO2CH2C6H5 can be synthesized by an SN2 reaction. Draw the structures of the alkyl chloride and nucleophile that will give this compound in highest yield. Use the wedge/hash bond tools to indicate stereochemistry where it exists. Include all valence lone pairs in your answer. Separate multiple reactants using the + sign from the drop-down menu. When a metal counterion is needed, use Na+, but draw it in its own sketcher.What are products formed from the below reaction?Draw the stereoisomers and name them
- (1, 3) Draw the structure(s) of the major organic product(s) of the following reaction. You do not have to consider stereochemistry. If a compound is formed more than once, add another sketcher and draw it again. Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate multiple products using the + sign from the drop-down menu.- For the dehydration shown, use curved arrows to show the formation of the carbocation intermediate in the presence of sulfuric acid H2SO4H2SO4, then draw the structure of the major product of the elimination. (Picture 1): Step 1: Use curved arrows to complete the protonation mechanism of the alcohol. Step 2: Use a curved arrow to show the formation of the carbocation intermediate. Note: HSO−4HSO4− is formed from step 1, but not shown. (Picture 2): Step 3: Use a curved arrow to show the carbocation rearrangement. Step 4: Draw curved arrows to show the elimination to form the major product. Water is added as a base. - Draw the major product of the elimination. H3O+H3O+ has been pre‑drawn for your convenience.Draw eugenol as a line structure. The double bonds of the benzene ring are fairly unreactive unless you use special catalysts. But the double bond on the side group is reactive. Draw the mechanism of eugenol reacting with HBr to form the two possible carbocation intermediates. Put your intermediates into square brackets. Label each carbocation as a methyl carbon or 1°, 2°, or 3°. Then circle a more stable carbocation if one is more stable. Can you guess what the final product is?
- Assume that 2-chloropropane reacts with CN− in an SN2 reaction. Use the JSME editor () to draw the structure of the substitution product of the reaction. The guide on how to draw your structure can be found here Important Note: When drawing the structures in the JME editor please adhere to the following formats: 1. If the nucleophile is OH−, DO NOT manually add the "H" to the final product 2. If the nucleophile is CN−, be sure to include the appropriate bonding between the C and N in the final productRearrangements can occur during the dehydration of 1° alcohols even though no 1° carbocation is formed—that is, a 1,2-shift occurs as the C— OH2+ bond is broken, forming a more stable 2° or 3° carbocation, as shown in Equation [1]. Using this information, draw a stepwise mechanism for the reaction shown in Equation [2]. We will see another example of this type of rearrangement in Section 16.5C.Start with condensed structural formula CH3-CH(OH)-CH(CH3)-CH2-CH(CH3)2 and react it first with H2SO4 and high heat, to produce a major substrate product. Then, take that major substrate product, and use it as the substrate of the next reaction, by reacting it with Br2 (in the presence of CH2Cl2 solvent), to produce the FINAL MAJOR substrate product. The complete correct condensed structural formula for the major substrate product after reaction step 1 is ___________. (If no new product is formed in this step, type "no reaction.") The complete correct condensed structural formula for the final major substrate product (after reaction step 2) is __________ . (If no new product is formed in this step, type "no reaction.")