During an electrolysis experiment, the following species are present in solution: H+, CH3COOH, CH3COO-, Na+, SO42-, H2O. The lead electrode dipped in the solution serves as the anode. Theoretically H2O, and Pb (s) are species that can be oxidized. Why is only Pb (s) oxidized during this experiment? because only solids can be oxidized because experimentally water can only be reduced because Pb (s) is a stronger oxidizing agent than water because Pb (s) is a stronger reducing agent than water
During an electrolysis experiment, the following species are present in solution: H+, CH3COOH, CH3COO-, Na+, SO42-, H2O. The lead electrode dipped in the solution serves as the anode. Theoretically H2O, and Pb (s) are species that can be oxidized. Why is only Pb (s) oxidized during this experiment? because only solids can be oxidized because experimentally water can only be reduced because Pb (s) is a stronger oxidizing agent than water because Pb (s) is a stronger reducing agent than water
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter17: Electrochemistry
Section: Chapter Questions
Problem 78QAP
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During an
Theoretically H2O, and Pb (s) are species that can be oxidized. Why is only Pb (s) oxidized during this experiment?
because only solids can be oxidized |
||
because experimentally water can only be reduced |
||
because Pb (s) is a stronger oxidizing agent than water |
||
because Pb (s) is a stronger reducing agent than water |
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