dvThe velocity of a given object is determined byoften used when examining air resistance, but do try to figure out where the method fails.) Att 0, the object is moving with a positive initial velocity of vo and continues until its velocityreaches zero (if it ever does).-kv", k> 0, n 2 0 a constant. (This is(a) Show that the object comes to a rest in a finite amount of time if and only if n < 1 and findthe maximum distance travelled in this case(b If 1 sn

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Asked Oct 14, 2019
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dv
The velocity of a given object is determined by
often used when examining air resistance, but do try to figure out where the method fails.) At
t 0, the object is moving with a positive initial velocity of vo and continues until its velocity
reaches zero (if it ever does).
-kv", k> 0, n 2 0 a constant. (This is
(a) Show that the object comes to a rest in a finite amount of time if and only if n < 1 and find
the maximum distance travelled in this case
(b If 1 sn<2, show that the maximum distance travelled by the object in a finite time is less
than (vo2-)/[(2 n)k].
(c) Show that if n 2 2, then there is no limit to the distance the object can travel.
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dv The velocity of a given object is determined by often used when examining air resistance, but do try to figure out where the method fails.) At t 0, the object is moving with a positive initial velocity of vo and continues until its velocity reaches zero (if it ever does). -kv", k> 0, n 2 0 a constant. (This is (a) Show that the object comes to a rest in a finite amount of time if and only if n < 1 and find the maximum distance travelled in this case (b If 1 sn<2, show that the maximum distance travelled by the object in a finite time is less than (vo2-)/[(2 n)k]. (c) Show that if n 2 2, then there is no limit to the distance the object can travel.

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Expert Answer

Step 1

(a). given that the differential equation describing the velocity of an object.

Integrate the equation,

dv
=-kv"
dt
77
SV"dv=_kj dt
kt
п -1
- v)
11
п —1
when n 1, 0sn<1, so 0-1-ns1
at t T, the particle comes at rest
1
(0-v")
п —1
kT =
1 y-n.
Т:
k1-n
this is a finite number)
0
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dv =-kv" dt 77 SV"dv=_kj dt kt п -1 - v) 11 п —1 when n 1, 0sn<1, so 0-1-ns1 at t T, the particle comes at rest 1 (0-v") п —1 kT = 1 y-n. Т: k1-n this is a finite number) 0

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Step 2

The distance travelled by the object can be calculated as follows,

dv dv ds
dt
ds ds
dv
= v
ds
=-kv"
vi-"dv-kds
0
integrate,v"dv=-k ds
2-n
S =
k(2-n)
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dv dv ds dt ds ds dv = v ds =-kv" vi-"dv-kds 0 integrate,v"dv=-k ds 2-n S = k(2-n)

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Step 3

(b). the maximum distance travelled by the object in...

S=
k(2-n)
when 1 n2,so 1 > 2 - n>0
so the maximum distance travelled by
the object in a finite time is less than the value
k(2-n)
help_outline

Image Transcriptionclose

S= k(2-n) when 1 n2,so 1 > 2 - n>0 so the maximum distance travelled by the object in a finite time is less than the value k(2-n)

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