Your assigned value of y is30The following fluids specific heats are used.FluidCommentsX (liquid)Y (ideal gas)Z (liquid)Cp4.2 kJ/(kg °C)1.01 kJ/(kg °C)2.03 kJ/(kg °C)does not change phaseR = 287 J/(kg K)does not change phaseNote: if any of these problems is impossible, state impossible, rather than a numerical answer.1) A shell-and-tube heat exchangerwith two shell passes and four tubeT shell, inpasses is used to heat (0.5 + y/40)kg/s of liquid Z from 10°C to 50°C.using 1.5 kg/s of liquid X entering atTrube,in(80 + y/2)°C. The over-all heattransfer coefficient is U = (150 – y)Figure 1: For use in Problem 5W/(m² °C).a. Find the exit temperature of Fluid X:Tx,out =°C (± 1°C)b. Find the required heat transfer surface area:A =m² (± 1%)

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e following fluids specific heats are used. Fluid Comments X (liquid) Y (ideal gas) Z (liquid) Cp 4.2 kJ/(kg °C) 1.01 kJ/(kg °C) 2.03 kJ/(kg °C) does not change phase R = 287 J/(kg K) does not change phase ote: if any of these problems is impossible, state impossible, rather than a numerical answer. 1) A shell-and-tube heat exchanger T shell, in with two shell passes and four tube passes is used to heat (0.5 + y/40) kg/s of liquid Z from 10°C to 50°C. using 1.5 kg/s of liquid X entering at Trube,in (80 + y/2)°C. The over-all heat transfer coefficient is U = (150 - w) %3D W/(m²°C). Figure 1: For use in Problem 5 a. Find the exit temperature of Fluid X: Tx,out = _°C (± 1°C) b. Find the required heat transfer surface area: A = m² (± 1%)

e following fluids specific heats are used. Fluid Comments X (liquid) Y (ideal gas) Z (liquid) Cp 4.2 kJ/(kg °C) 1.01 kJ/(kg °C) 2.03 kJ/(kg °C) does not change phase R = 287 J/(kg K) does not change phase ote: if any of these problems is impossible, state impossible, rather than a numerical answer. 1) A shell-and-tube heat exchanger T shell, in with two shell passes and four tube passes is used to heat (0.5 + y/40) kg/s of liquid Z from 10°C to 50°C. using 1.5 kg/s of liquid X entering at Trube,in (80 + y/2)°C. The over-all heat transfer coefficient is U = (150 - w) %3D W/(m²°C). Figure 1: For use in Problem 5 a. Find the exit temperature of Fluid X: Tx,out = _°C (± 1°C) b. Find the required heat transfer surface area: A = m² (± 1%)

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter5: Analysis Of Convection Heat Transfer

Section: Chapter Questions

Problem 5.8P

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