E = sign(æ) · (300 N/C)i where sign(æ) = c < 0 and sign(x) = +1 if x > 0. A cylinder of ngth 20 cm and radius 4.0 cm has its center at the gin and its axis along the r-axis such that one end

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
Publisher:OpenStax
Chapter6: Gauss's Law
Section: Chapter Questions
Problem 55P: The electric field 10.0 cm from the surface of a copper ball of radius 5.0 cm is directed toward the...
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An electric field is given
by E = sign(x) · (300 N/C)î where sign(x) = –1
if x < 0 and sign(x) = +1 if x > 0. A cylinder of
length 20 cm and radius 4.0 cm has its center at the
origin and its axis along the x-axis such that one end is
at x = +10 cm and the other is at x = –10 cm.
|
What is the net charge inside the cylinder?
A. 2.7 × 10¬11 C
B. 2.7 × 10¬7 C
C. 9.3 × 10¬11 C
D. 1.3 × 10º C
Transcribed Image Text:An electric field is given by E = sign(x) · (300 N/C)î where sign(x) = –1 if x < 0 and sign(x) = +1 if x > 0. A cylinder of length 20 cm and radius 4.0 cm has its center at the origin and its axis along the x-axis such that one end is at x = +10 cm and the other is at x = –10 cm. | What is the net charge inside the cylinder? A. 2.7 × 10¬11 C B. 2.7 × 10¬7 C C. 9.3 × 10¬11 C D. 1.3 × 10º C
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