educing NO Emissions Adding NH3 to the stack gases at an electric power generating plant can reduce NOx emissions. This selective noncatalytic reduction (SNR) process depends on the reaction between NH3 (an odd-electron compound) and NO. $$4NH3(g)+6NO(g)5N2(g)+6H2O(g) The following kinetic data were collected at 1200 K. Experiment [NH3] (M) [NO] (M) Rate (M/s) 1 1.00x10-5 1.00x10-5 0.120 2 2.00x10-5 1.00x10-5 0.240 3 2.00x10-5 1.50x10-5 0.360 4 2.50x10-5 1.50x10-5 0.450 What is the rate-law expression for the reaction? Do not add multiplication symbols to your answer.
educing NO Emissions Adding NH3 to the stack gases at an electric power generating plant can reduce NOx emissions. This selective noncatalytic reduction (SNR) process depends on the reaction between NH3 (an odd-electron compound) and NO. $$4NH3(g)+6NO(g)5N2(g)+6H2O(g) The following kinetic data were collected at 1200 K. Experiment [NH3] (M) [NO] (M) Rate (M/s) 1 1.00x10-5 1.00x10-5 0.120 2 2.00x10-5 1.00x10-5 0.240 3 2.00x10-5 1.50x10-5 0.360 4 2.50x10-5 1.50x10-5 0.450 What is the rate-law expression for the reaction? Do not add multiplication symbols to your answer.
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter11: Chemical Kinetics
Section: Chapter Questions
Problem 11.49PAE: The rate of photodecomposition of the herbicide piclo- ram in aqueous systems was determined by...
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Reducing NO Emissions Adding NH3 to the stack gases at an electric power generating plant can reduce
NOx emissions. This selective noncatalytic reduction (SNR) process depends on the reaction between NH3 (an odd-electron compound) and NO.
$$4NH3(g)+6NO(g)5N2(g)+6H2O(g)
The following kinetic data were collected at 1200 K.
NOx emissions. This selective noncatalytic reduction (SNR) process depends on the reaction between NH3 (an odd-electron compound) and NO.
$$4NH3(g)+6NO(g)5N2(g)+6H2O(g)
The following kinetic data were collected at 1200 K.
Experiment | [NH3] (M) | [NO] (M) | Rate (M/s) |
1 | 1.00x10-5 | 1.00x10-5 | 0.120 |
2 | 2.00x10-5 | 1.00x10-5 | 0.240 |
3 | 2.00x10-5 | 1.50x10-5 | 0.360 |
4 | 2.50x10-5 | 1.50x10-5 | 0.450 |
What is the rate-law expression for the reaction? Do not add multiplication symbols to your answer.
$$Rate=
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