Einstein mixed 15.0 g of Cu and combined it with 46.0 g of HNO3  according to the reaction 3Cu + 8HNO3 ⟶⟶ 3Cu(NO3)2 + 2NO + 4H2 Which reactant is limiting? How many grams of Hydrogen are produced?

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Q: phosphorus (P), with an atomic weight of 31, combines with hydrogen (H), with an atomic weight of 1,…

A: We will use stoichiometry of the reaction to get the answer

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A: The reaction of magnesium nitrate and tin – 2Mg(NO3)2 + Sn →Sn(NO3)4+2Mg

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A: The reaction taking place can be written as  => H2 (g) + O2 (g) ---------> H2O (l)  Balancing…

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A: Given: Mass of X2 = 0.7971 g Atoms of X2 = 3.0×1022 NA = 6.023×1023 mol-1

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Q: What mass of H2SO4 is produced from 6.58 g of SO3 and 1.64 g of H2O?

A: Given that there are 6.58 g of SO3 and 1.64 g of H2O to produce H2SO4

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Q: How many grams of carbon dioxide could be made from the combustion of 5.3 g of propane, C3H8, and…

A: The balanced chemical reaction is, C3H8 + 5O2 → 3CO2 + 4H2O That is, 1 mole of propane(C3H8) react…

Q: When 25.5 grams of C5H10 undergoes combustion with a 75.0 g sample of oxygen, how many grams of…

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Q: how many grams of aluminum are required to produce 17.5 grams of hydrogen?

A: Given :- 6 NaOH + 2Al --> 2Na3 ALO3+3H2                 mass of H2 = 17.5 g   To be calculated :-…

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Q: If 5.99 g of ethylene (C2H4) are combusted with 6.10 g of oxygen. How many grams of CO2 are formed?…

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Q: Part B IF 12.0 g of MgSO, 7H O is thoroughly heated, what mass of anhydrous magnesium sulfate will…

A: Given : Mass of MgSO4.7H2O = 12g

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A: Here we are asked, How many grams of oxygen are required toproduce 46.2 g of water vapor.

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A: We know that, Percent yield = (Actual yield) / (Theoretical yield)

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A: The provided balanced equation:  2 H2   +     O2   →   2 H2O 2 mol      1 mol        2mol Molar Mass…

Q: purified KNO3

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A: Welcome to bartleby !

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Q: 5. Given the following equation, what mass (in grams) of AICI, can be produced from 4.4 g of Al and…

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Q: Question attached

A: Mass of water is calculated as follows: Hydrate = anhydrous salt + watermass of water=mass of…

Q: When 64.7 g of HI (127.9 g/mol) forms from the reaction of hydrogen gas with excess iodine, how many…

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A: Given :  amount of He given = 27.8g  moles of He required = 6.89 moles

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