Question
Asked Oct 7, 2019
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A 32.0−g sample of an unknown metal at 99
°
C was placed in a constant-pressure calorimeter containing 80.0 g of water at 24.0
°
C. The final temperature of the system was found to be 28.4
°
C. Calculate the specific heat of the metal. (The heat capacity of the calorimeter is 10.4 J/
°
C.)
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Expert Answer

Step 1

Given:

Mass of sample = 32.0 g

T = 99 0C

Mass of water = 80

T of water = 240C

Final T = 28.40C

Heat capacity of the calorimeter is 10.4 J/ °C

specific heat of the metal = ?

Step 2

Heat lost by metal = mass x specific heat x temperature change of metal

                              = 32 X Specific heat X (99 – 24)

Assume that the specific heat = c and simplify,

Heat lost by metal = 2400 C

 

Heat gained by water = mass x specific heat x temperature change of water

                                   = 80 X 4.184 X (28.4 - 24.0) 

                       &...

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General Chemistry

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