enthaipy of fomation of pneno enthaipy formation of pienoi gaseous Carb -393.51 kJ mol1 2C6H5OH + 1502 → 12C02 + 6H20 O a. .2202.9 kJ mol"1 O b.514,3 kJ mol"1 Oc.3053.5 kJ mol"1 Od.844.3 kJ mol1

Chemistry: An Atoms First Approach
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Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter16: Spontaneity, Entropy, And Free Energy
Section: Chapter Questions
Problem 104CP: The standard enthalpy of formation of H2O(l) at 298 K is 285.8 kJ/mol. Calculate the change in...
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Calculate the standard enthalpy of formation of phenol, C 6H5OH, at 298.15 K given that, at this temperature, the standard enthalpy of formation of phenol is -165.0 kJ mol1, of liquid water, H20 is -285.8 kJ mol-1 and gaseous carbon dioxide, CO2, is
-393.51 kJ mol-1
2C6H5OH + 1502 → 12CO2 + 6H20
O a. .2202.9 kJ mol-1
O b.-514.3 kJ mol-1
O c. .3053.5 kJ mol-1
O d.-844.3 kJ mol-1
Transcribed Image Text:Calculate the standard enthalpy of formation of phenol, C 6H5OH, at 298.15 K given that, at this temperature, the standard enthalpy of formation of phenol is -165.0 kJ mol1, of liquid water, H20 is -285.8 kJ mol-1 and gaseous carbon dioxide, CO2, is -393.51 kJ mol-1 2C6H5OH + 1502 → 12CO2 + 6H20 O a. .2202.9 kJ mol-1 O b.-514.3 kJ mol-1 O c. .3053.5 kJ mol-1 O d.-844.3 kJ mol-1
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