Estimate the relative uncertainty for the measured quantity R according to the following equation: R = (157(±25) - 59(+4))/(1220(±108) + 77(+11)) O 0.27 O 0.4 O 0.2 0.51
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- To test the quality of the work of a commercial laboratory, duplicate analyses of apurified benzoic acid (68.8% C, 4.953% H) sample were requested. It is assumed that therelative standard deviation of the method is sr → = 4 ppt for carbon and 6 ppt forhydrogen. The means of the reported results are 68.5% C and 4.882% H. At the 95%confidence level, is there any indication of systematic error in either analysis?Estimate the absolute deviation(or uncertainty) for the results of the following calculations. Round each result so that it contains only significant digits. The numbers in parentheses are absolute standard deviations. Finally, write the answer and its uncertainty.a.) Y= 6.75 (± 0.03) + 0.843(±0.001) - 5.021 (±0.001) = 2.572b.) Y= 19.97(± 0.04) + 0.0030(±0.0001) + 4.29(±0.08) = 24.263c.) Y= 143(± 6) - 64(±3) = 5.9578 x10-21249 (±1) +77 (±8)An analysis of city drinking water for total hardness was done by two students in the laboratory and produced the following results (in ppm CaCO3): Student A: 228.3, 226.4, 226.9, 227.1, and 228.6. Student B: 229.5, 226.1, 230.7, 223.8, and 227.5What is the 95% confidence interval for the mean?
- A volumetric calcium analysis on samples of the blood serum of a patient believed to be suffering from a hyperparathyroid condition produced the following data: mmol Ca/L = 3.10, 3.08, 3.28, 3.15, 3.26, 3.12, 3.14, 3.18, 3.25, 3.11, 2.95. Calculate: Mean Standard deviation Coefficient of variation What is the 95% confidence interval for the mean of the data, assuming no prior information about the precision of the analysis? Apply the Q test to the following data sets to determine whether the outlying result should be retained or rejected at the 95% confidence level. ( work on the first measurements according to your case)The following data were obtained in order to determine the density of a cylindrical metal bar. If the accepted value for the density of the bar is 6.70 g/cm^3, what is the percent relative error?What is the relative error in the ppt of the following data if the accepted value is 70.05 M? 70.24 M, 70.22 M and 70.10 M
- Chemistry The levels of an organic pollutant (P) in the groundwater at the perimeter of a plant were a cause for concern. A 10 mL sample of the water was taken and the pollutant was extracted with 95% efficiency using 25 mL of diethyl ether. GC was used to analyse the concentration of P in diethyl ether. A calibration curve was plotted for a series of standards of P which yielded the following results: Peak Area Toluene Conc. (µg/ml) 12,000 2.6 23,700 5.0 35,500 7.7 46,800 9.9 31,250 Sample Determine the concentration of P in ppb in the initial groundwater sample.A powder was prepared containing 3.00% NaCN and 97.00% NaCl. A sample obtained from that mixture containing 7.374×10^5 particles weighs 10.0 g. Determine the number and percent relative standard deviation of NaCN particles from a sample of the mixture weighing 6.30 g. I need nNaCN particles and %RSDTypes of Error; Propagation of Uncertainty from Random ErrorYou prepare an NH3 [FM 17.030 5 (±0.000 2)] solution by diluting 7.36 (±0.03) mL of a 28.00 (±0.05) wt% NH3 solution [density = 0.899 (±0.003) g/mL] to a final volume of 500.00 (±0.02) mL. Find the molarity of the NH3 solution along with its absolute uncertainty.
- What is the median of the values 7.79, 8.24, 5.81, 4.97, 1.04, 7.39, and 7.22?1) Report the results of this calculation along with both the percent relative and absolute uncertainties. 417.3 ± 0.4 × 71.8 ± 0.7(647.21 ± 0.2 − 182.3 ± 0.4) Absolute uncertainty:Percent uncertainty:Estimate the absolute standard deviation (or uncertainty) for the results of the following calculations. Round each result so that it contains only significant digits. The numbers in parentheses are absolute standard deviations. Show your solution and express the final answer and its corresponding uncertainty. a) y= 2.998(±0.002) - 3.98 (±0.15) + 9.035 (±0.002) = 8.0531 b) y= 39.2(±0.3) x 3.054 (±0.022) x 10^ -2 = 1.197 c) y= [198(±6) - 89 (±3)] / 1335 (±2) + 64 (±7)] = 7.791 x 10^-2
