Estimate, with 95% confidence level, the true proportion of low-income people who will vote for the introduction of the tax. b/ Can we conclude at the 5% level of significance that the proportion of high-income voters favoring the new security tax is 10% higher than that of low-income voters?

Estimate, with 95% confidence level, the true proportion of low-income people who will vote for the introduction of the tax. b/ Can we conclude at the 5% level of significance that the proportion of high-income voters favoring the new security tax is 10% higher than that of low-income voters?

College Algebra (MindTap Course List)

12th Edition

ISBN:9781305652231

Author:R. David Gustafson, Jeff Hughes

Publisher:R. David Gustafson, Jeff Hughes

Chapter8: Sequences, Series, And Probability

Section8.7: Probability

Problem 58E: What is meant by the sample space of an experiment?

See similar textbooks

Related questions

Q: recent poll, 490 people were asked if they liked dogs, and 45% said they did. Find the margin of…

A: Given that Sample size n =490 Sample proportion p=45%=0.45

Q: recent poll, 470 people were asked if they liked dogs, and 40% said they did. Find the margin of…

A: The critical value at 99% confidence level from standard normal table will be: Following…

Q: Suppose that the state of Nebraska wants to take a poll on the proportion of its citizens who…

A: Sample size: The minimum sample size for a desired confidence level, α with a given margin of error,…

Q: In a recent poll, 420 people were asked if they liked dogs, and 9% said they did. Find the Margin of…

A: Given: Sample size=n=420,Number of people who liked dogs:x=420×9100=37.8≈38,Significance…

Q: A gubernatorial candidate wants to analyze how she is performing with different.age groups. Her…

A: We are 99% confident the difference in population proportions of people 18-24 years old who plan to…

Q: In a public opinion survey, 60 out of a sample of 70 high-income voters and 90 out of a sample of…

Q: 9) The Genetics and IVF Institute conducted a clinical trial of the YSORT method designed to…

Q: A political candidate has asked his/her assistant to conduct a poll to determine the percentage of…

A: Here we need to find the required sample size. Since nothing is mentioned about the population…

Q: In a survey of health workers, 25 percent stated that they expect to be promoted after 3 years of…

A: From the provided information, 25 percent stated that they expect to be promoted after 3 years of…

Q: A Gallop poll wants to determine the proportion of people who plan on voting for neither the…

A: From the provided information, Total respondents (n) = 500 Number of people who say they plan on…

Q: 2. In a study to estimate the proportion of residents in a certain city and its suburbs who favor…

A: Given that X1=450 X2=240 N1=1000 N2=800 P1=0.45 P2=0.3

Q: 4. A college dean reported that 80% of all students majoring in Math are males. If 62 out of the 80…

A: 4] Followings are the explanation of the question Use the One sample z proportion test The…

Q: Construct a 95% confidence interval for the difference between population proportion of voters in…

Q: A survey of 90 community members was conducted to measure if community members favored opening a new…

A: It is given that sample size (n) is 90 and x is 68.

Q: In a recent poll, 290 people were asked if they liked dogs, and 40% said they did. Find the Margin…

Q: A political candidate has asked his/her assistant to conduct a poll to determine the percentage of…

A: Obtain the sample size of a no preliminary estimate for p. The formula of sample size is, Use EXCEL…

Q: In a recent poll, 310 people were asked if they liked dogs, and 40% said they did. Find the Margin…

A: Given data: n = 310p⏞ = 40100=0.40C.I = 99% =0.99Then, calculate αα = 1-0.99 =0.01Now,…

Q: In a study, 68% of 900 randomly selected adults said they believe the Republicans favor the rich. If…

A: Given that, P⏞=68%=0.681-P⏞=1-0.68=0.32n=900E=2%=0.02 Now,…

Q: In a sample of 271 people, 153 said they would vote for candidate B. What is the upper bound of a…

A: Given that In a sample of 271 people, 153 said they would vote for candidate B. Sample size (n) =…

Q: A state’s Department of Commerce reports that 82 percent of all small businesses that applied for a…

A: The margin of error is, E = 0.0525, If the prior information is unknown, assume the value of sample…

Q: A political candidate has asked his/her assistant to conduct a poll to determine the percentage of…

A: The random variable percentage of people in the community that supports him/her follows binomial…

Q: A TV news reporter says that a proposed constitutional amendment is likely to win approval in the…

A: The random variable vote percentage follows binomial distribution. The sample size is 2500. The…

Q: in a recent poll, 130 people were asked if they liked dogs, and 46% said they did. Find the Margin…

A: Introduction: The 100 (1 – α) % confidence interval for the population proportion, p is: Here, n is…

Q: A poll is taken among residents of a city and its suburbs to determine the feasibilities of a…

A: Confidence interval: It is defined as the range which contains the value of the true population…

Q: In a recent research poll, 83.4% of 500 randomly selected men in the U. S. knew the name of our…

A: There are two independent samples which are men and women. We have to construct 95% confidence…

Q: In a survey of 1200 adults, 562 said that they plan to watch the next Olympics on television. Using…

A: Givenx=562n=1200p^=xn=5621200=0.4683confidence interval = 95%

Q: n a recent poll, 230 people were asked if they liked dogs, and 70% said they did. Find the margin of…

A: It is given that the n = 230 and p hat is 0.70.

Q: A pollster is going to sample a number of voters in a large city and construct a 98% confidence…

A: Given: Confidence level is 98% Margin of error is 0.05 Required: To find the sample size.

Q: A survey of 927 voters in one state reveals that 537 fever approval of an issue before the…

A: We have given that, Favorable cases (X) = 537 and sample size (n) = 927 Then, We will find the 95%…

Q: A newsgroup is interested in constructing a 99% confidence interval for the proportion of all…

A: Let p be the population proportion of all Americans who are in favor of a new Green initiative. The…

Q: A political candidate has asked his/her assistant to conduct a poll to determine the percentage of…

A: Given data, E=6%=0.06 z-value at 99% confidence is Zc=2.576 Let p=0.5 n=?

Q: In a recent poll, 390 people were asked if they liked dogs, and 33% said they did. Find the Margin…

A: Given p^=Sample proportion=0.33 n=sample size=390 Confidence interval = 99%

Q: A national health organization warns that 30% of the middle school students nationwide have been…

A: Given Data Sample Size, n = 110 Number of successes, x = 21

Q: In an exit poll of 625 scientifically and randomly selected voters, 340 expressed support for…

A: The sample proportion of voters in the poll who support Carpetbagger can be calculated as: Thus,…

Q: A 99% confidence interval for the difference in the proportion of registered voters that support…

Q: A survey of 300 union members in New York State reveals that 112 favor the Republican candidatefor…

A: Given information- Confidence level, c = 98% Population proportion of all New York State union…

Q: A political candidate has asked his/her assistant to conduct a poll to determine the percentage of…

A: Given information Error = 5% = 0.05 Confidence level = 0.95

Q: In a recent poll, 390 people were asked if they liked dogs, and 83% said they did. Find the Margin…

A: We want to find the margin of error

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A: When nothing is known about the proportion, consider population proportion to be p=0.50…

Q: A political candidate has asked his/her assistant to conduct a poll to determine the percentage of…

Q: In a sample of 150 people from town A, 45% planned to vote for the proposition. In a sample of 200…

A: From the provided information,

Q: A political candidate has asked his/her assistant to conduct a poll to determine the percentage of…

A: We have to find sample size for given data..

Q: In a recent poll, 380 people were asked if they liked dogs, and 75% said they did. Find the margin…

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A: Given that, Margin of error = 3% = 0.03 99% confidence level

Q: A random sample of 1,000 voters was drawn and asked on a bipartisan basis about their voting…

A: Givensample size(n)=1000x=610confidence interval=95%

Q: A political candidate has asked his/her assistant to conduct a poll to determine the percentage of…

A: Using Excel formula "=NORM.S.INV(1-(0.01/2))" (or standard normal distribution table), the z-value…

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A: Given Data: Margin of error=0.02 Significance level=0.025 Critical value at 0.025 significance…

Question

In a public opinion survey, 80 out of a sample of 100 high-income
voters and 55 out of a sample of 80 low-income voters supported the introduction of a new
national security tax.
a/ Estimate, with 95% confidence level, the true proportion of low-income people who will
vote for the introduction of the tax.
b/ Can we conclude at the 5% level of significance that the proportion of high-income voters
favoring the new security tax is 10% higher than that of low-income voters?

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Similar questions

What is meant by the sample space of an experiment?
In a public opinion survey, 60 out of a sample of 70 high-income voters and 90 out of a sample of 100 low-income voters supported the introduction of a new national security tax. a/ Estimate, with 95% confidence level, the true proportion of low-income people who will vote for the introduction of the tax. b/ Can we conclude at the 5% level of significance that the proportion of high-income voters favoring the new security tax is lower than that of low-income voters?
In a recent poll, from a sample of 300 likely voters, 175 answered they approve the way the president is handling his job. Compute the lower limit of the 90% confidence interval for the proportion of voters who approve the way the president is handling his job.
In a survey funded by the UW school of medicine, 750 of 1,000 adult Seattle residents said they did not vote in the last election and 893 of 1,123 Denver residents said they did not vote in the election.Construct a 95% confidence interval of the difference in proportions (Seattle minus Denver) residents who did not vote in the last election. (.0809, .0095) (-.0809, -.0095) (-.0809, .0095) (-.0095, .0809)
A random sample of 1,000 voters was drawn and asked on a bipartisan basis about their voting intentions ahead of the recent animal federal election. A total of 610 people said they would vote for the Cat Party. Calculate the 95% confidence interval for the proportion of voters who intend to vote for the Cat Party. Interpret confidence intervals based on this poll and comment on the chances of the Dog Party returning to power.
A political candidate has asked you to conduct a poll to determine what percentage of people support her. If the candidate only wants a 2% margin of error at a 99% confidence level, what sample size is needed?
A TV news reporter says that a proposed constitutional amendment is likely to win approval in the upcoming election because in a poll of 2500 likely voters, 1283 said they would vote in favor of the constitutional amendment. a) Calculate a 98% confidence interval for the percentage of voters that will vote in favor of the constitutional amendment . b) What is the marginal error for a 98% confidence interval? Do not compute this by hand, use your interval from part a . c) Does the poll support the news reporters’ claim that the amendment is likely to pass (ie. does the interval appear to agree with a vote over 50%)? Why or why not ?
In a sample of 150 people from town A, 45% planned to vote for the proposition. In a sample of 200 people from town B, 67% planned to vote for the proposition. Compute the 95% confidence interval for the difference in the percent of the populations that plan to vote for the proposition (use town A for population 1). Enter the lower limit to 4 decimal places.