In a survey of 1200 adults, 562 said that they plan to watch the next Olympics on television. Using these sample statistics, calculate the margin of error, E, for a 95% confidence interval for the proportion of all adults that plan to watch the next Olympics on television.

Q: In a four-year psychedelic-mushroom experiment, 93 of the 300 subjects reported experiencing “strong…

A: Obtain the point estimate for the percentage of all people who experience “strong or extreme fear”…

Q: In a random sample on 200 airline passengers, 84 said they would like a window seat. What is the…

A: 1. The point estimate for the proportion of passengers wishing a window seat is, p^=xn=84200=0.42…

Q: A university dean is interested in determining the proportion of students who receive some sort of…

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Q: In your work for a real estate company, you find that in a sample of 1762 home buyers, 722 found…

A: Given Data: x=722 n=1762   p^=7221762=0.4098

Q: When 460 junior college students were surveyed, 100 said they have a passport. Construct a 95%…

A: Given that there are 460 junior college students and 100 said they have a passport. That is, n=460…

Q: In a survey of 2344 ​adults, 715 say they believe in

A: Given that there are 2344 adults and 715 say they believe in UFOs. Consider the sample proportion,…

Q: We surveyed 53 people in an attempt to determine the proportion of Americans who lease a vehicle. 13…

A: The proportion of sample Americans who lease a vehicle is, Thus, the proportion of sample Americans…

Q: From a survey of 400 new Wawasan Open University students chosen at random, it was discovered that…

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Q: In each of Exercises, use the one-proportion plus-four z-interval procedure to find the required…

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Q: uman resources managers, 71% of respondents felt they should hire new staff within the next three…

A: The Upper limit can be calculated as: Upper limit = Point estimate (sample proportion) + Margin of…

Q: In a survey of 50,00 people, 80% indicated that they listened to their favorite radio station…

A: Hern= 5000 P^ = 0.80 We have to construct 95% ci for p

Q: A university dean is interested in determining the proportion of students who receive some sort of…

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Q: Of 380 randomly selected medical​ students, 21 said that they planned to work in a rural community.…

A: Given that 380 randomly selected medical​ students, 21 said that they planned to work in a rural…

Q: In a survey of 1200 adults, 562 said that they plan to watch the next Olympics on television. Using…

A: Formula for calculating Margin of error :  ME=Zα/2 * √p̂(1-p̂)/n

Q: In a Harvard School of Public Health survey, 2105 of 10,904 randomly selected U.S. college students…

A: Given data is appropriate for testing of hypothesis. Because it is a large sample test for single…

Q: In a recent poll, 240 people were asked if they liked dogs, and 32% said they did. Find the margin…

A: Find z-critical value:…

Q: Of 400 randomly selected medical students, 21 said that they planned to work in a  rural community.…

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Q: airline has surveyed a simple random sample of air travelers to find out whether they would be…

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Q: Of 380 randomly selected medical students, 210 said that they planned to work in a rural community.…

A: Solution: Let X be the number of medical students said that they planned to work in a rural…

Q: in a recent poll, 220 people were asked if they liked dogs, and 36% said they did . find the margin…

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Q: search for the Ford Motor Company, you find that a random sample of 800 households includes 721 in…

A: At 98% confidence level, the z value is 2.33 which can be obtained by using the standard normal…

Q: In a poll of 2,500 likely voters, 966 say that the Philippines spend too little on education. Find…

A: Ans- Given the level of confidence interval   90 %                                        Then   α =…

Q: In a recent poll, 260 people were asked if they liked dogs, and 67% said they did. Find the margin…

A: Given: p = 67%=0.67 n= 260 The value of z at a 90% confidence level is 1.645, which can be found by…

Q: In a survey of 1000 people, 850 said they would not to travel to Disney World this summer. Construct…

A: Given: n=1000 and x=850 Then,p^=xn=8501000=0.85

Q: In simple random sample of 150 of workers, 22 said their workplace environment is toxic. Construct a…

A: We have to find out given confidence interval..

Q: In a survey of 1007 parents of children ages 8 to 14, 75% say they are willing to get a second job…

A: Given information- A proportion of parents say they are willing to get a second job or part-time…

Q: To find the proportion of San Diegans subscribed to Disney+ in 2019, a researcher randomly selected…

A: Given that, n=200 p^=101200=0.505

Q: Of 254 randomly selected medical students, 25 said that they planned to work in a rural community.…

A: It is given that, the number of students said that they planned to work in natural community   (x)…

Q: 2. In a survey of 1024 US adults, 287 said that their favorite sport to watch is football. a. Find a…

A: It is given that the survey contains 1024 US adults and the number of US adults who favorite sport…

Q: An internet service provider sampled 540 customers and found that 55 of them experienced an…

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Q: In a recent poll, 430 people were asked if they liked dogs, and 54% said they did. Find the margin…

A: In a recent poll, 430 people were asked if they liked dogs, and 54% said they did. Find the margin…

Q: A study was being done to estimate the proportion of students who receive financial aid. If the…

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Q: Construct a 95% confidence interval for the proportion of college students who say they own their…

A: Given : n=410 , X=155  , α=0.05 We want to find the 95% confidence interval for the proportion of…

Q: Assume a nationwide random survey of 800 adults asked about attitudes toward “alternative medicine”…

A: We have given that,  Sample size (n) = 800 and Favorable cases (X) =448 Then,  We will find the 99%…

Q: In a survey of 1024 US adults, 287 said that their favorite sport to watch is football. a. Find a…

A: From the provided information, Sample size (n) = 1024 Out of which 287 said that their favourite…

Q: n a recent Zogby International Poll, nine of 48 respondents rated the likelihood of a terrorist…

A: Given that : x = 9 n = 48

Q: To find the proportion of San Diegans subscribed to Disney+ in 2019, a researcher randomly selected…

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Q: In a survey of 32 students at a local high school, 17 support changing the schools mascot. Find the…

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Q: The Pizza Shop wanted to determine what of its customers ordered an only cheese pizza. Out of 90…

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Q: A recent study of 750 internet users in Europe found that 35% of internet users were women. What is…

A: It is given that the study of 750 internet users in Europe found that 35% of internet users were…

Q: A college administrator is interested in determining the proportion of students who receive some…

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Q: At one large college, 660 out of the 1500 students surveyed said they plan to take another science…

A: Given that,   x=660,n=1500 The sample proportion is, Critical values: By using the standard normal…

Q: In a recent poll, 410 people were asked if they liked dogs, and 44% said they did. Find the margin…

A: n = 410 p^=0.44 Confidence interval = 95%

Q: In a poll of 2,300 likely voters, 966 say that the Philippines spend too little on education. Find…

A: We have given that the sample size n = 2300, favourable cases X =966 and sample proportion p =…

Q: In a recent poll, 570 people were asked if they liked dogs, and 14% said they did. Find the margin…

A: From the Standard Normal Table, the z value for 95% level is 1.96.

Q: According to a poll taken in a certain​ country, when adults were asked whether they were​ thriving,…

A: Sample size (n) = 439 240 of them said that they were struggling that is x = 240. The sample…

Q: f a Random Sample of 450 adults includes 155 who identify as happy, compute an 80% confidence…

A: Given data,n=450x=155sample proportion p=xn=155450=0.34z-value at 80% confidence is Zc=1.282

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community.…

A: Here we need to construct a 95% confidence interval for the population proportion. Here the sample…