Everest auto industry produces bearing for Mahindra Motor Corporation. The precision of radius of bearing is very important for its successful functioning. To check the variability in the bearing radius, the company randomly selected ten bearings and measured the radius, the result of which is as shown in the table below. #no Nominal radius (cm) #no Nominal radius (cm) 1 2.70 6 2.59 2 2.65 7 2.73 3 2.75 8 2.64 4 2.55 9 2.88 5 2.76 10 2.83 Calculate the sample standard deviation for the above data. Construct a box plot and check whether there is any outlier data in the data distribution. Based on the comparison between the mean and the quartile, identify the shape of the data distribution. Calculate the 65th percentile and interpret the result. What is the range of the data distribution? Explain its meaning.
Everest auto industry produces bearing for Mahindra Motor Corporation. The precision of radius of bearing is very important for its successful functioning. To check the variability in the bearing radius, the company randomly selected ten bearings and measured the radius, the result of which is as shown in the table below. #no Nominal radius (cm) #no Nominal radius (cm) 1 2.70 6 2.59 2 2.65 7 2.73 3 2.75 8 2.64 4 2.55 9 2.88 5 2.76 10 2.83 Calculate the sample standard deviation for the above data. Construct a box plot and check whether there is any outlier data in the data distribution. Based on the comparison between the mean and the quartile, identify the shape of the data distribution. Calculate the 65th percentile and interpret the result. What is the range of the data distribution? Explain its meaning.
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 13PPS
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Everest auto industry produces bearing for Mahindra Motor Corporation. The precision of radius of bearing is very important for its successful
#no |
Nominal radius (cm) |
#no |
Nominal radius (cm) |
1 |
2.70 |
6 |
2.59 |
2 |
2.65 |
7 |
2.73 |
3 |
2.75 |
8 |
2.64 |
4 |
2.55 |
9 |
2.88 |
5 |
2.76 |
10 |
2.83 |
- Calculate the sample standard deviation for the above data.
- Construct a box plot and check whether there is any outlier data in the data distribution.
- Based on the comparison between the mean and the
quartile , identify the shape of the data distribution. - Calculate the 65th percentile and interpret the result.
- What is the
range of the data distribution? Explain its meaning.
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