Exactly 0.2220 g of pure NazCO; was dissolved in 100.0 mL of 0.0731 M HCI. What mass in grams of CO2 were evolved? Na2CO3 + 2HCI → 2NaCl + CO2 + H2O Na=23 C=12 0=16 CI=35.5 H=1
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- Exactly 0.1120g of pure Na2CO3 was dissolved in 100.0 ml of 0.0497 M HClO 4 . What mass in grams of CO 2 was evolved?A mixture containing only KCl and NaBr is analyzed by the Mohr Method. A 0.3172-g sample is dissolved in 50 mL water and titrated to the Ag2CrO4 endpoint, requiring 36.85 mL of 0.1120 M AgNO3. A blank titration requires 0.71 mL of titrant to reach the same endpoint. Report the % (w/w) KCl and NaBr in the sample. [Answer should be 82.41 % (w /w)]A 0.1093-g sample of impure Na2CO3 was analyzed by the Volhard Method. After adding 50.00 mL of 0.06911 M AgNO3, the sample was back titrated with 0.05781 M KSCN, requiring 27.36 mL to reach the end point. Report the purity of Na2CO3sample.
- A sample weighing 0.6760 g that contains an unknown amount of BaCl₂ was completely dissolved in water and treated with an excess of sodium sulfate. Na2SO4 A precipitate of BaSO4 formed which was dried and weighed, yielding 0.4105 g. What percentage of the original sample was BaCl₂? 39.77 24.15 35.72 69.78 54.180.500 g of an impure ammonium sulfate sample is dissolved in water and treated with an excess of NaOH; The mixture is distilled, and the distillate is taken up in 50.00 mL of 0.2000 M HCl. The solution obtained is titrated with 19.70 mL of 0.2000 M NaOH. Calculate the purity (%) of the ammonium sulfate (MW, 132.14) in the original sample.A 0.1093-g sample of impure Na2CO3 was analyzed by the Volhard Method. After adding 50.00 mL of 0.06911 M AgNO3, the sample was back titrated with 0.05781 M KSCN, requiring 27.36 mL to reach the end point. Report the purity of Na2CO3 sample.
- Percentage purity of a sample of 0.1350 g of As2O3 assayed iodometrically using 23.5 mL of 0.1055N iodine solutionA mixture containing only KCl and NaBr is analyzed by the Mohr method. A 0.5072-g sample is dissolved in 50 mL of water and titrated to the Ag2CrO4 end point, requiring 36.85 mL of 0.1120 M AgNO3. A blank titration requires 0.71 mL of titrant to reach the same end point. Report the %w/w KCl and NaBr in the sample.KCl = 74.551 NaBr = 102.89A 0.1093-g sample of impure Na2CO3( Molecular weight 106) was analyzed by the Volhard method. After adding 50.00 mL of 0.06911 M AGN03 (Molecular weight 169.87), the sample was back titrated with 0.05781 M KSCN, requiring 27.36 mL to reach the end point. Report the purity of the Na2CO3 sample.
- An analysis for borohydride ion is based on its reaction with Ag+: BH4- + 8Ag+ + 8OH- → H2BO3- + 8Ag(s) + 5H2O The purity of a quantity of KBH4 to be used in an organic synthesis was established by diluting 3.258g of the material to exactly 500.0mL, treating a 100.0 mL aliquot with 50.00 mL of 0.2639M AgNO3 and titrating the excess silver ion with 3.36 mL of 0.0397 M KSCN. Calculate the percent purity of the KBH4 [Report the numerical value of the result to two decimal places - NO UNITS]A 1.250 g sample of cheese was subjected to a Kjeldahl analysis to determine the amount of protein. The sample was digested, the nitrogen is oxidized to NH₄⁺, and was then converted to NH₃ with NaOH, and distilled into a collection flask containing 50.00 mL of 0.1050 M HCl. The excess HCl is back titrated with 0.1175 M NaOH, this required 21.65 mL to reach the bromothymol blue end point. A. How many moles of N is present in the cheese sample? B. Report the %N of the cheese sample. C. Report the %protein of the cheese sample, assuming that there are 6.4 grams of protein for every gram of nitrogenA 1.250 g sample of cheese was subjected to a Kjeldahl analysis to determine the amount of protein. The sample was digested, the nitrogen is oxidized to NH₄⁺, and was then converted to NH₃ with NaOH, and distilled into a collection flask containing 50.00 mL of 0.1050 M HCl. The excess HCl is back titrated with 0.1175 M NaOH, this required 21.65 mL to reach the bromothymol blue end point. What is the reaction for the digestion of the limestone sample A. 2 NaOH + CaCO₃ ⇌ Na₂CO₃ + Ca(OH)₂ B. 2 HCl + CaCO₃ ⇌ CaCl₂ + H₂O + CO₂ C. CaCO₃ ⇌ CaO + CO₂ D. NaOH + HCl ⇌ NaCl + H₂O