Example 1:- A 60 kg person walking at 1 m/sec (~2mph) bumps into a wall and stops in a distance of 2.5cm in about 0.05 sec. what is the force developed on impact ? A(mv) = (60 kg ) (1 m/sec) - (60 kg) (0 m/sec) = (60 kg.m/sec) %3D

Example 1:- A 60 kg person walking at 1 m/sec (~2mph) bumps into a wall and stops in a distance of 2.5cm in about 0.05 sec. what is the force developed on impact ? A(mv) = (60 kg ) (1 m/sec) - (60 kg) (0 m/sec) = (60 kg.m/sec) %3D

Inquiry into Physics

8th Edition

ISBN:9781337515863

Author:Ostdiek

Publisher:Ostdiek

Chapter3: Energy And Conservation Laws

Section: Chapter Questions

Problem 2C: A bullet with a mass of 0.01 kg is tired horizontally into a block of wood hanging on a string. The...

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to decelerate
Example 1:-
A 60 kg person walking at 1 m/sec (~2mph) bumps into a wall and stops in a
distance of 2.5cm in about 0.05 sec. what is the force developed on impact ?
A(mv) = (60 kg ) (1 m/sec) - (60 kg) (0 m/sec) = (60 kg.m/sec)

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