At the same instant that a 0.50 kg ball is dropped from a distance of 25 m above the ground, a second ball, with a mass of 0.25 kg, is launched vertically from the ground with an initial velocity of 15 m/s. The trajectories of the balls are close, but allow them to pass each other without colliding. After 2.0 s, the height of the center of mass of the two balls system in relation to the ground is: Use gravity acceleration g = 9.8 m/s2 a) 2.9 meters. b)4.0 meters. c) 10.4 meters. d) 5.0 meters. e) 7.1 meters

Q: Two objects, both with a mass of 1.87 kg are sliding across a horizontal, frictionless surface…

A:

Q: Two objects, both with a mass of 1.89 kg are sliding across a horizontal, frictionless surface…

A: given: m1=m2=1.89 kg v1 = 4.99 i m/s v2 = -2.16 i m/s let final velocity= v

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A:

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A: mass of first particle (m) = 1.80 kg Velocity of first particle (u) = 1.60i^ - 3.50j^ msmass of…

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A: M = 600 g  m = 5.75 g  height, h = 50 cm

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A: The given values are,

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A:

Q: A 0.032-kg bullet is fired vertically at 230 m/s into a 0.15-kg baseball that is initially at rest.…

A: Solution: Given that mass of bullet, m = 0.032-kg  mass of basket ball, M = 0.15 kg v of bullet =…

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A:

Q: A 2.30-kg particle has a velocity (2.20 î − 4.50 ĵ) m/s, and a 3.50-kg particle has a velocity (1.00…

A: Given,

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A: Hai, since there are multiple sub parts posted, we will answer the first three sub parts. (a)

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Q: In an experiment designed to determine the velocity of a bullet fired by a certain gun, a wooden…

A: M = 600 g  m = 5.75 g  h = 50 cm

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A: The momentum of the system is conserved when no external force is applied. Momentum = mass x…